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使用相同值按块分组 pandas dataframe

[英]Grouping pandas dataframe by blocks using identical values

I have a big dataframe which is structured as follows:我有一个大的 dataframe,其结构如下:
|'Type'| |'类型'| |'col2'| |'col2'| |'col3'| |'col3'|
| | ----- | ----- | | | -----| -----| |-----| |-----|
'A' '一个'
'B' '乙'
'C' 'C'
'C' 'C'
'C' 'C'
'B' '乙'
C C
C C
C C
A一个
B
C C
C C
B
C C
A一个

So the types are like hierarchies;所以类型就像层次结构; As with one or multiple Bs, which have one or multiple Cs.与具有一个或多个 C 的一个或多个 B 一样。 I would like to split up this dataframe into 2 different kinds of chunks:我想把这个 dataframe 分成两种不同的块:

  • 1 chunk from A until the next A (all B's with C's for each A)从 A 到下一个 A 的 1 个块(所有 B 和每个 A 的 C)
  • 1 chunk within each A chunk, from B until the next B (all C's for each B within an A)每个 A 块中的 1 个块,从 B 到下一个 B(A 中每个 B 的所有 C)

How can I do this?我怎样才能做到这一点?

IIUC, you want col2 to have groups starting with A and col3 subgroups starting with B: IIUC,您希望 col2 具有以 A 开头的组和以 B 开头的 col3 子组:

df['col2'] = df['Type'].eq('A').cumsum()
df['col3'] = df['Type'].eq('B').groupby(df['col2']).cumsum()

output: output:

   Type  col2  col3
0     A     1     0
1     B     1     1
2     C     1     1
3     C     1     1
4     C     1     1
5     B     1     2
6     C     1     2
7     C     1     2
8     C     1     2
9     A     2     0
10    B     2     1
11    C     2     1
12    C     2     1
13    B     2     2
14    C     2     2
15    A     3     0

You can then use col2/col3 to groupby :然后,您可以使用 col2/col3 到groupby

m = df[['col2', 'col3']].ne(0).all(1)
for name, g in df[m].groupby(['col2', 'col3']):
    print(f'group {name}')
    print(g)

output: output:

group (1, 1)
  Type  col2  col3
1    B     1     1
2    C     1     1
3    C     1     1
4    C     1     1
group (1, 2)
  Type  col2  col3
5    B     1     2
6    C     1     2
7    C     1     2
8    C     1     2
group (2, 1)
   Type  col2  col3
10    B     2     1
11    C     2     1
12    C     2     1
group (2, 2)
   Type  col2  col3
13    B     2     2
14    C     2     2

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