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将 C++ 方法传递给 Objective-C 方法

[英]Passing a C++ method to an Objective-C method

I have a C++ class ' Expression ' with a method I'd like to use in my Objective-C class ' GraphVC '.我有一个 C++ 类“ Expression ”,其中有一个我想在我的 Objective-C 类“ GraphVC ”中使用的方法。

class Expression {
    double evaluate(double);
}

And my Objective-C class:还有我的 Objective-C 课程:

@implementation GraphVC : UIViewController {
- (void)plot:(double(*)(double))f;
@end

I thought that it would be easiest to pass around function pointers that take a double and return a double, as opposed to C++ objects, but I haven't had much success using functional.h .我认为传递带有双精度值并返回双精度值的函数指针是最容易的,而不是 C++ 对象,但是我使用functional.h .h 并没有取得太大的成功。 What's the best way to use my C++ method from Objective-C?从 Objective-C 使用我的 C++ 方法的最佳方法是什么?

EDIT: Thanks for your quick responses.编辑:感谢您的快速回复。 Allow me to elaborate a bit... I have a backend written in C++ where I manipulate objects of type Expression.请允许我详细说明一下...我有一个用 C++ 编写的后端,我可以在其中操作 Expression 类型的对象。 There's subclasses for rational, polynomial, monomial, etc. My initial idea was to use mem_fun from , but I wasn't able to get code compiling this way.有理数、多项式、单项式等的子类。我最初的想法是使用mem_fun from ,但我无法以这种方式编译代码。 I also had trouble using bind1st to bind the this pointer.我也无法使用 bind1st 绑定this指针。

  • Writing an Objective-C wrapper is a possibility, but I'd rather use the already existing evaluate() function, and I don't want to break the clean separation between the backend and the iPhone GUI classes.编写一个Objective-C 包装器是一种可能,但我更愿意使用已经存在的evaluate()函数,而且我不想打破后端和iPhone GUI 类之间的清晰分离。
  • I can't have a global expression or use a static method (I need to plot arbitrary Expression instances.我不能有全局表达式或使用静态方法(我需要绘制任意Expression实例。

I should have more explicitly stated that I need to pass a C++ member function (not a static function or existing C function) to an Objective-C object.我应该更明确地声明我需要将 C++ 成员函数(不是静态函数或现有的 C 函数)传递给 Objective-C 对象。 Has anyone had luck using C++'s <functional> to turn member functions into pointers I can use in an Objective-C object, or should I use an Objective-C wrapper?有没有人使用 C++ 的<functional>将成员函数转换为我可以在 Objective-C 对象中使用的指针,还是应该使用 Objective-C 包装器?

If you want to make a pointer to a method in C++, you need to include the class name, like this:如果要在 C++ 中创建指向方法的指针,则需要包含类名,如下所示:

class Foo
{
  public:
    double bar(double d)
    {
      return d;
    }
};

void call_using_obj_and_method(Foo *f, double (Foo::*m)(double d))
{
  (f->*m)(3.0);
}

int main()
{
  Foo f;
  call_using_obj_and_method(&f, &Foo::bar);
  return 0;
}

Note that you need an instance of the class as well.请注意,您还需要一个类的实例。 In my example this is another parameter, though you could let it be a global variable, or a singleton instance of class Foo.在我的示例中,这是另一个参数,尽管您可以将其设为全局变量,或者类 Foo 的单例实例。

Though, like jkp said, you can also solve the problem by making the method static or turning it into a regular function.不过,就像 jkp 所说的,您也可以通过使方法静态或将其转换为常规函数来解决问题。

EDIT: I'm not sure if I understand your question correctly.编辑:我不确定我是否正确理解您的问题。 I don't think you need to use functional.我认为您不需要使用功能性。 Here is how my example would look in Objective-C++:下面是我的示例在 Objective-C++ 中的样子:

#include <Cocoa/Cocoa.h>

class Foo
{
  public:
    double bar(double d)
    {
      return d;
    }
};

typedef double (Foo::*fooMethodPtr)(double d);

@interface Baz : NSObject
{
}
- (void)callFooObj:(Foo *)f method:(fooMethodPtr)m;
@end

@implementation Baz
- (void)callFooObj:(Foo *)f method:(fooMethodPtr)m
{
  (f->*m)(3.0);
}
@end

int main()
{
  Foo f;
  Baz *b = [[Baz alloc] init];
  [b callFooObj:&f method:&Foo::bar];
  return 0;
}

I would suggest wrapping the C++ class in an Objective-C class, and then also providing a我建议将 C++ 类包装在一个 Objective-C 类中,然后还提供一个

- (void) plotWithObject:(id)obj
{
   double result = [obj evaluate: 1.5];
   // ... etc ...
}

in addition to the plot: method.除了情节:方法。

I think the problem here is that you are trying to pass a member function of your Expression class to the Objective-C class.我认为这里的问题是您试图将Expression类的成员函数传递给 Objective-C 类。 This will not work because it's expecting a this pointer as the first argument to that function (therefore the signature is not the same as the one expected by the plot: method.这将不起作用,因为它期望this指针作为该函数的第一个参数(因此签名与plot:方法期望的签名不同。

If you make the C++ method a static, you can do this, but then you don't buy yourself a lot over using a standard C function.如果您使 C++ 方法成为静态方法,则可以这样做,但是您不会因为使用标准 C 函数而付出太多代价。

IE, if the Expression class looked like this: IE,如果Expression类如下所示:

class Expression {
    static double evaluate(double);
}

You should be able to call it like this:你应该可以这样称呼它:

[self plot:myExpression.evaluate(&Express::evalulate)];

As I say though, there isn't a huge amount of value in this because you may as well be using a standard C function (unless you can do something in the C++ class that is more useful to you).不过,正如我所说,这并没有太大的价值,因为您也可能使用标准的 C 函数(除非您可以在 C++ 类中做一些对您更有用的事情)。

I did once look at trying to bridge boost::bind() results with objective-c methods but didn't get very far.我曾经尝试过使用 Objective-c 方法来桥接 boost::bind() 结果,但并没有走得太远。 I'm sure if you dig deep enough in the C++ runtime you could do it though.我敢肯定,如果您在 C++ 运行时中挖掘得足够深,您可以做到。

If your C++ member function returns a double, can't your code just look like this?如果你的 C++ 成员函数返回一个 double,你的代码不能看起来像这样吗?

- (void)plot:(double)f;

... ...

[self plot:myExpression.evaluate(aDouble)];

Or something similar.或者类似的东西。 I've not used much mixing of Obj-C and C++, but this is how I would approach it.我没有使用太多 Obj-C 和 C++ 的混合,但这就是我将如何处理它。 You also might have to have a .mm extension on your Objective-C++ file if you're mixing them like that.如果你像这样混合它们,你可能还需要在你的 Objective-C++ 文件上有一个 .mm 扩展名。

Why wouldn't you pass the instantiated c++ class around inside an NSValue and then call the c++ method directly?为什么不在 NSValue 内部传递实例化的 c++ 类,然后直接调用 c++ 方法?

- (NSValue*)getExpression
{
    Expression* e = new Expression();
    return [[NSValue alloc] initWithPointer:e];
}

- (void)callExpression(NSValue*)expression
{
    Expression* e = [expression pointerValue];
    e->evaluate();
}

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