[英]Pandas.Series.ewm for calculating a RSI Indicator, with Wilders Moving Average
I asked a question earlier today.我今天早些时候问了一个问题。 I have found a partial Solution to it: pandas.Series.ewm
我找到了部分解决方案:pandas.Series.ewm
Data: I have a Series, see example数据:我有一个系列,请参阅示例
1 54.8
2 56.8
3 57.85
4 59.85
5 60.57
6 61.1
7 62.17
8 60.6
9 62.35
10 62.15
11 62.35
12 61.45
13 62.8
14 61.37
15 62.5
16 62.57
17 60.8
18 59.37
19 60.35
20 62.35
21 62.17
22 62.55
23 64.55
24 64.37
25 65.3
26 64.42
27 62.9
28 61.6
29 62.05
30 60.05
31 59.7
32 60.9
33 60.25
34 58.27
35 58.7
36 57.72
37 58.1
38 58.2
date close change gain loss avg_gain avg_loss rs rsi
1 54.8
2 56.8 2 2 0
3 57.85 1.05 1.05 0
4 59.85 2 2 0
5 60.57 0.72 0.72 0
6 61.1 0.53 0.53 0
7 62.17 1.07 1.07 0
8 60.6 -1.57 0 1.57
9 62.35 1.75 1.75 0
10 62.15 -0.2 0 0.2
11 62.35 0.2 0.2 0
12 61.45 -0.9 0 0.9
13 62.8 1.35 1.35 0
14 61.37 -1.43 0 1.43
15 62.5 1.13 1.13 0 0.842857143 0.292857143 2.87804878 74.21383648
16 62.57 0.07 0.07 0 0.787653061 0.271938776 2.896435272 74.33551618
17 60.8 -1.77 0 1.77 0.731392128 0.378943149 1.930084053 65.87128622
18 59.37 -1.43 0 1.43 0.679149833 0.454018638 1.495863333 59.93370364
19 60.35 0.98 0.98 0 0.700639131 0.421588735 1.661901925 62.43287589
20 62.35 2 2 0 0.793450622 0.391475254 2.026821908 66.96204698
21 62.17 -0.18 0 0.18 0.736775577 0.376369879 1.957583798 66.18861651
22 62.55 0.38 0.38 0 0.711291607 0.349486316 2.035248805 67.05377173
23 64.55 2 2 0 0.803342207 0.324523008 2.475455322 71.22679168
24 64.37 -0.18 0 0.18 0.745960621 0.314199936 2.374159048 70.36298569
25 65.3 0.93 0.93 0 0.759106291 0.291757083 2.601843568 72.23644
26 64.42 -0.88 0 0.88 0.704884413 0.333774435 2.111858608 67.86486387
27 62.9 -1.52 0 1.52 0.654535526 0.418504832 1.563985589 60.99822072
28 61.6 -1.3 0 1.3 0.607782989 0.481468773 1.262351835 55.79821031
29 62.05 0.45 0.45 0 0.596512775 0.447078146 1.334247224 57.15963631
30 60.05 -2 0 2 0.55390472 0.558001136 0.992658768 49.81579304
31 59.7 -0.35 0 0.35 0.514340097 0.543143912 0.946968356 48.63809691
32 60.9 1.2 1.2 0 0.563315804 0.504347918 1.116919064 52.76153835
33 60.25 -0.65 0 0.65 0.523078961 0.514751638 1.016177361 50.40118893
34 58.27 -1.98 0 1.98 0.485716178 0.619412235 0.784156577 43.9511076
35 58.7 0.43 0.43 0 0.481736451 0.575168504 0.837557077 45.5799217
36 57.72 -0.98 0 0.98 0.447326705 0.60408504 0.740502868 42.54534031
37 58.1 0.38 0.38 0 0.442517654 0.560936108 0.788891369 44.09945638
38 58.2 0.1 0.1 0 0.418052108 0.520869243 0.802604709 44.52472054
Formulas in Excel Excel 中的公式
change: previous_close - current_close更改:previous_close - current_close
gain: =IF(change>0; change; 0)增益:=IF(变化>0;变化;0)
loss: =IF(change<0; -change; 0)损失:=IF(变化<0;-变化;0)
avg_gain (first row): =AVERAGE("over the first n gains") avg_gain (第一行): =AVERAGE("在前 n 个增益上")
5. avg_gain (every next row): =(prev. avg_gain * (n - 1) + current gain) / n 5. avg_gain (每下一行): =(prev. avg_gain * (n - 1) + current gain) / n
7. avg_loss (every next row): =(prev. avg_loss * (n - 1) + current loss) / n 7. avg_loss(每下一行):=(prev. avg_loss * (n - 1) + current loss) / n
rs: avg_gain / avg_loss rs: avg_gain / avg_loss
rsi: 100-(100/(1+rs)) rsi: 100-(100/(1+rs))
Formula in Python for change, gain and loss : (works perfectly fine) Python 中用于更改、增益和损失的公式:(效果很好)
delta = data.diff()
delta_up = delta.clip(lower=0)
delta_down = delta.clip(upper=0).abs()
Problem: I have to formulas but I cant combine them.问题:我必须使用公式,但我无法将它们组合起来。
Formula for the first average gain/loss : (on its own it works)第一个平均收益/损失的公式:(它本身有效)
The first Average needs to be an Simple Moving Average第一个平均线需要是一个简单的移动平均线
first_avg_gain = delta_up.rolling(
window=periods, min_periods=periods
).mean()[: periods + 1]
first_avg_loss = delta_down.rolling(
window=periods, min_periods=periods
).mean()[: periods + 1]
Formula for the following average gains/losses :以下平均收益/损失的公式:
This is calculated like that in Excel: (prev. avg_gain * (period_length - 1) + gain)/period_length这与 Excel 中的计算类似:(prev. avg_gain * (period_length - 1) + gain)/period_length
The Formula following should do the same下面的公式应该做同样的事情
avg_gain = delta_up.ewm(
com=periods - 1, adjust=False, min_periods=periods
).mean()
avg_loss = delta_down.ewm(
com=periods - 1, adjust=False, min_periods=periods
).mean()
Formula in Python for rs and rsi : rs 和 rsi的 Python 中的公式:
rs = avg_gain / avg_loss
indicator = 100 - 100 / (1 + rs)
Question: How can I combine first_avg_gain and avg_gain / first_avg_loss and avg_loss?问题:如何结合 first_avg_gain 和 avg_gain / first_avg_loss 和 avg_loss?
I need to implement this code, but it doesnt work我需要实现这段代码,但它不起作用
for i, row in enumerate(df['avg_gain'].iloc[window_length+1:]):
df['avg_gain'].iloc[i + window_length + 1] =\
(df['avg_gain'].iloc[i + window_length] *
(window_length - 1) +
df['gain'].iloc[i + window_length + 1])\
/ window_length
for i, row in enumerate(df['avg_loss'].iloc[window_length+1:]):
df['avg_loss'].iloc[i + window_length + 1] =\
(df['avg_loss'].iloc[i + window_length] *
(window_length - 1) +
df['loss'].iloc[i + window_length + 1])\
/ window_length
I cannot reproduce your example with periods = 10
.我无法使用
periods = 10
重现您的示例。 Feels like there's something fishy about your SMA.感觉你的 SMA 有问题。 With
periods = 14
: periods = 14
:
df = (df
.assign(
change = df.diff(),
gain = lambda df_: df_.change.clip(0),
loss = lambda df_: df_.change.clip(upper=0).abs(),
avg_gain = lambda df_: df_.gain.rolling(window=14, min_periods=14).mean(),
avg_loss = lambda df_: df_.loss.rolling(window=14, min_periods=14).mean(),
rs = lambda df_: df_.avg_gain.div(df_.avg_loss),
rsi = lambda df_: 100-100/(1+df_.rs)
)
)
close change gain loss avg_gain avg_loss rs rsi
--- --- --- --- --- --- --- --- ---
--- --- --- --- --- --- --- --- ---
14 62.50 1.13 1.13 0.00 0.843 0.293 2.878 74.214
15 62.57 0.07 0.07 0.00 0.705 0.293 2.407 70.651
16 60.80 -1.77 0.00 1.77 0.630 0.419 1.503 60.041
17 59.37 -1.43 0.00 1.43 0.487 0.521 0.934 48.300
18 60.35 0.98 0.98 0.00 0.506 0.521 0.970 49.235
19 62.35 2.00 2.00 0.00 0.611 0.521 1.171 53.943
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