为什么我的代码只有在我注释掉“break;”时才有效？

Question

I am trying to solve a LeetCode question ( 26. Remove Duplicates from Sorted Array ) and my code was not working until I commented out "break;". Could someone explain why this is so? Here's my code:

class Solution {
    public int removeDuplicates(int[] nums) {
        int read = 0;
        int write = 0;
        
        for (int i = 0; i < nums.length; i++) {
            int found = 0;
            for (int j = 0; j < nums.length; j++) {
                if ((nums[i] == nums[j]) && (i != j) && (j < i))
                    found = 1;
                   // break;
                }
            
            if (found == 0) {
                nums[write] = nums[read];
                write++;
            }
            
            read++;
            
        }
        return write;
    }
}

Answer 1

Indent your code correctly, and you'll see that the corresponding part reads as:

            int found = 0;
            for (int j = 0; j < nums.length; j++) {
                if ((nums[i] == nums[j]) && (i != j) && (j < i))
                    found = 1;
                break;
            }

You can see, that the break is not only executed if the condition holds true but in every iteration, so also in the first one. The loop terminates as soon as you've inspected the case j == 0 which is incorrect, of course.

As you want to terminate the loop only if the condition holds true, just put the two lines after the if-statement into a code block:

            int found = 0;
            for (int j = 0; j < nums.length; j++) {
                if ((nums[i] == nums[j]) && (i != j) && (j < i)) {
                    found = 1;
                    break;
                } 
            }