MongoDB 如何使用 $match 查找多个文档

Question

I have a collection like this

{
 "name": "Sai Darshan"
}
{
 "name": "Sathya"
}
{
 "name": "Richie"
}

I want to match the documents with the name "Sathya" and "Richie".

How can I achieve this using $match . I currently tried this

$db = $this->dbMongo->selectDB("userData");
$collection = $db->selectCollection("userObject");

$aggregationFields = [
      [
        '$match' => [
          'name'=> 'Sathya',
          'name'=> 'Richie',
        ]
      ]
 ];

$cursor = $collection->aggregate($aggregationFields)->toArray();

Currently I am getting only the document

{
 "name": "Richie"
}

I am expecting to fetch both documents ie the documents with the name "Sathya" and "Richie". I expect to do this with $match itself because I have further pipelines I want to pass this data to.

Is there anyway I can achieve this?. Any help is appreciated.

Thank you.

Answer 1

@nimrod serok answered in the comments , which is to use the $in operator .

What is probably happening in with the query in the description is that the driver is de-duplicating the name entry. So the query that the database receives only includes the filter for 'name'=> 'Richie' . You can see some reference to that here in the documentation , and javascript itself will also demonstrate this behavior:

> filter = { name: 'Sathya', name: 'Richie' };
{ name: 'Richie' }
>