[英]Forward a variadic instance method call via a pointer to member function in C++
I'm working on a class representation utility that would work in a similar way to Java's Class
class. That is, a mechanism that would emulate class reflection.我正在研究 class 表示实用程序,它的工作方式与 Java 的Class
class 类似。也就是说,一种可以模拟 class 反射的机制。
#include <map>
#include <stdexcept>
#include <string>
template<typename Class>
struct class_repr {
std::map<std::string, uintptr_t> fields;
std::map<std::string, void* (Class::*)(...)> methods;
void declare_field(const std::string& name, void* pointer) {
fields[name] = reinterpret_cast<uintptr_t>(pointer);
}
template<typename R, typename ...Params>
void declare_instance_method(const std::string& name, R (Class::* pointer)(Params...)) {
methods[name] = (void* (Class::*)(...)) pointer;
}
template<typename Tp>
Tp& get_field(void* object, const std::string& name) {
if (fields.count(name) == 0) throw std::invalid_argument("Field " + name + " not declared in the class descriptor");
return *reinterpret_cast<Tp*>(uintptr_t(object) + fields.at(name));
}
template<typename R, typename ...Params>
requires std::is_same_v<R, void>
void invoke_instance_method(void* object, const std::string& name, Params&& ... params) {
if (methods.count(name) == 0) throw std::invalid_argument("Method " + name + " not declared in the class descriptor");
(reinterpret_cast<Class*>(object)->*methods.at(name))(std::forward<Params>(params)...);
}
template<typename R, typename ...Params>
requires (not std::is_same_v<R, void>)
R invoke_instance_method(void* object, const std::string& name, Params&& ... params) {
if (methods.count(name) == 0) throw std::invalid_argument("Method " + name + " not declared in the class descriptor");
return *static_cast<R*>((reinterpret_cast<Class*>(object)->*methods.at(name))(std::forward<Params>(params)...));
}
};
And below is the class I'm testing it with:下面是我正在测试的 class:
#include <iostream>
class cat {
std::string name, color;
[[nodiscard]] const std::string& get_name() {
return name;
}
[[nodiscard]] const std::string& get_color() {
return color;
}
void say(std::string&& what) {
std::cout << "[" << name << "]: " << what << std::endl;
}
void meow() {
say("meow");
}
void say_color() {
say("my fur is " + color);
}
public:
cat(std::string name, std::string color) : name(std::move(name)), color(std::move(color)) {}
static class_repr<cat> get_representation() {
class_repr<cat> descriptor;
descriptor.declare_field("name", &(static_cast<cat*>(nullptr)->name));
descriptor.declare_field("color", &(static_cast<cat*>(nullptr)->color));
descriptor.declare_instance_method("get_name", &cat::get_name);
descriptor.declare_instance_method("get_color", &cat::get_color);
descriptor.declare_instance_method("say", &cat::say);
descriptor.declare_instance_method("meow", &cat::meow);
descriptor.declare_instance_method("say_color", &cat::say_color);
return descriptor;
}
};
This code works fine:此代码工作正常:
int main() {
cat kitty("marble", "white");
class_repr cat_class = cat::get_representation();
cat_class.get_field<std::string>(&kitty, "name") = "skittle";
cat_class.get_field<std::string>(&kitty, "color") = "gray";
cat_class.invoke_instance_method<void>(&kitty, "meow");
cat_class.invoke_instance_method<void>(&kitty, "say_color");
std::cout << cat_class.invoke_instance_method<std::string>(&kitty, "get_name") << "'s color is indeed "
<< cat_class.invoke_instance_method<std::string>(&kitty, "get_color") << std::endl;
return 0;
}
But when I try to call the say
function, the code doesn't compile because non-primitive type objects cannot be passed through variadic method:但是当我尝试调用say
function 时,代码无法编译,因为非原始类型对象无法通过可变参数方法传递:
cat_class.invoke_instance_method<void, std::string&&>(&kitty, "say", "purr"); // error
Is there any way around making this work as intended (so that it calls an equivalent of kitty.say("purr")
)?有没有办法让这项工作按预期进行(这样它就相当于调用kitty.say("purr")
)?
You can create a class representing any member function using type erasure (modified from this SO answer ) .您可以创建一个 class 代表任何成员 function 使用类型擦除(从这个 SO 答案修改) 。 No void*
, no C-stype ellipsis ...
.没有void*
,没有 C 型省略号...
#include <memory>
#include <any>
#include <vector>
#include <functional>
class MemberFunction
{
public:
template <typename R, typename C, typename... Args>
MemberFunction(R (C::* memfunptr)(Args...))
: type_erased_function{
std::make_shared<Function<R, C, Args...>>(memfunptr)
}
{}
template <typename R, typename C, typename... Args>
R invoke(C* obj, Args&&... args){
auto ret = type_erased_function->invoke(
std::any(obj),
std::vector<std::any>({std::forward<Args>(args)...})
);
if constexpr (!std::is_void_v<R>){
return std::any_cast<R>(ret);
}
}
private:
struct Concept {
virtual ~Concept(){}
virtual std::any invoke(std::any obj, std::vector<std::any> const& args) = 0;
};
template <typename R, typename C, typename... Args>
class Function : public Concept
{
public:
Function(R (C::* memfunptr)(Args...)) : func{memfunptr} {}
std::any invoke(std::any obj, std::vector<std::any> const& args) override final
{
return invoke_impl(
obj,
args,
std::make_index_sequence<sizeof...(Args)>()
);
}
private:
template <size_t I>
using Arg = std::tuple_element_t<I, std::tuple<Args...>>;
template <size_t... I>
std::any invoke_impl(std::any obj, std::vector<std::any> const& args, std::index_sequence<I...>)
{
auto invoke = [&]{
return std::invoke(func, std::any_cast<C*>(obj), std::any_cast<std::remove_reference_t<Arg<I>>>(args[I])...);
};
if constexpr (std::is_void_v<R>){
invoke();
return std::any();
}
else {
return invoke();
}
}
R (C::* func)(Args...);
};
std::shared_ptr<Concept> type_erased_function;
};
You store a std::map<std::string, MemberFunction>
in your class_repr
and change your declare_instance_method
and invoke_instance_method
like so:您将std::map<std::string, MemberFunction>
存储在class_repr
中,并像这样更改declare_instance_method
和invoke_instance_method
:
template<typename R, typename ...Params>
void declare_instance_method(const std::string& name, R (Class::* pointer)(Params...)) {
methods.insert({name, MemberFunction(pointer)});
}
template<typename R, typename ...Params>
requires std::is_same_v<R, void>
void invoke_instance_method(Class* object, const std::string& name, Params&& ... params) {
if (methods.count(name) == 0) throw std::invalid_argument("Method " + name + " not declared in the class descriptor");
methods.at(name).invoke<void>(object, std::forward<Params>(params)...);
}
template<typename R, typename ...Params>
requires (not std::is_same_v<R, void>)
R invoke_instance_method(Class* object, const std::string& name, Params&& ... params) {
if (methods.count(name) == 0) throw std::invalid_argument("Method " + name + " not declared in the class descriptor");
return methods.at(name).invoke<R>(object, std::forward<Params>(params)...);
}
Note that this is a prototype.请注意,这是一个原型。 To make this generally applicable you still need to invest quite a bit of work: You have to consider const member functions and const arguments, member functions mutating inputs or returning references etc. Also note, that std::any
stores by value, so you might create some unnecessary copies of the function arguments.为了使其普遍适用,您仍然需要投入大量工作:您必须考虑 const 成员函数和 const arguments,成员函数改变输入或返回引用等。另请注意, std::any
按值存储,因此您可能会创建 function arguments 的一些不必要的副本。
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