Python 子进程找不到 Pythonpath 模块

Question

I am trying to use subprocess.run(['python3.9', "scripts/example.py"], check=True) .

example.py uses a module, that I have added to the PYTHONPATH. However, whenever I run the above line, the module is not found.

The confusing part for me is, that printing sys.path inside of example.py I do see the path to my module. But when I am running os.system("which python") or os.system("echo $PYTHONPATH") inside example.py, it returns/prints nothing.

Answer 1

Looks like you need to check the doc forthe env parameter of subprocess.run and set it appropriately.

Side note: typically you would want to use the exact same Python interpreter for the sub-process call, so you would write: subprocess.run([sys.executable, 'scripts/example.py'], ...) , unless of course you really do want 'python3.9' explicitly and nothing else (which would be surprising).