[英]Regex/shell parameters expensions when using cp.spawnSync
I'm testing in the command line a jq command:我正在命令行中测试 jq 命令:
jq -f config/jest.jq -s reports/jest/*.json
Which outputs the content of 3 json files located under /reports/jest/
, accordings to the filters I've specified under /config/jest.jq
.根据我在
/config/jest.jq
下指定的过滤器,它输出位于/reports/jest/
下的 3 个 json 文件的内容。
If I try to run the same thing within a node script like so however:但是,如果我尝试像这样在节点脚本中运行相同的东西:
const jq = await cp.spawnSync('jq', ['-f', configPath, '-s', folderPath]);
It fails - jq.stderr tells me he can't finds " /reports/jest/*.json
".它失败了——jq.stderr 告诉我他找不到“
/reports/jest/*.json
”。 If I do this however:但是,如果我这样做:
const jq = await cp.spawnSync('jq', ['-f', configPath, '-s', 'reports/jest/app.json', 'reports/jest/backend.json', ]);
Then it properly pipes both files into jq.然后它将两个文件正确地通过管道传输到 jq。 Why is my regular expression working in the command line, but not under spawnSync?
为什么我的正则表达式在命令行中有效,但在 spawnSync 下却无效? How do I need to adapt it so it reads all my json file & parse it as a single large input?
我需要如何调整它才能读取我所有的 json 文件并将其解析为单个大输入?
That's not a regular expression, but a shell glob (or shell wildcard pattern).这不是正则表达式,而是 shell glob(或 shell 通配符模式)。 It is evaluated by your shell (sh, bash, zsh, …).
它由您的 shell(sh,bash,zsh,...)评估。
spawnSync
is not running a shell, but executing the binary directly, passing all arguments verbatim. spawnSync
没有运行 shell,而是直接执行二进制文件,逐字传递所有 arguments。
If you need a shell's behavior, you must execute a shell or resolve the wildcard somehow else.如果您需要 shell 的行为,则必须执行 shell 或以其他方式解析通配符。 Here's a version which uses a shell:
这是一个使用 shell 的版本:
const jq = await cp.spawnSync(
'sh',
[
'-c',
'jq -f ' + configPath + ' -s ' folderPath
]);
Or要么
const jq = await cp.spawnSync(
'sh',
[
'-c',
['jq -f', configPath, '-s', folderPath].join(' ')
]);
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