如何在正则表达式中排除一行的一部分

Question

Out of the line Your name is: "Foo Bar" I want to select Foo Bar in regex only.

I have tried non-capturing groups without success: (?:^Your name is: ").*(?:")$

"(.*?)" Works but I don't want the double quotes to be selected

Answer 1

As you tagged pcre , you don't have to use a lookbehind assertion but you can match the text and then use \K to forget what is matched so far.

^Your name is: "\K.+(?="$)

See a regex demo .

Or without lookarounds at all and a capture group:

^Your name is: "(.+)"$

See another regex demo .

Answer 2

You can use lookbehind and lookahead :

(?<=^Your name is: ").+(?="$)

(?<= looks behind for Your name is: " and (?= looks ahead for " .

The result will be whatever is between that.

regex101