我的代码有错误。 有指针的东西我似乎无法修复它

Question

I was practicing pointers and classes and I tried to print the members of the class after I put a value. But an error appears that's something to do with pointers and the char array.

Error (active) E0167 argument of type "const char *" is incompatible with parameter of type "char *"
Error (active) E0167 argument of type "const char *" is incompatible with parameter of type "char *"
Error C2664 'void car::setName(char [])': cannot convert argument 1 from 'const char [4]' to 'char []'
Error C2664 'void car::setColor(char [])': cannot convert argument 1 from 'const char [4]' to 'char []'

#include <iostream>
#include <cstring>
#include <algorithm>
using namespace std;

class car {
private:
    char name[15];
    char color[10];
    int maxspeed;
    int model;

public:
    void setName(char  n[])
    {
        strcpy_s(name, n);
    }
    void setColor(char n[])
    {
        strcpy_s(color, n);
    }
    void setMaxspeed(int m)
    {
        maxspeed = m;
    }
    void setModel(int m)
    {
        model = m;
    }
    char* getName()
    {
        return name;
    }
    char* getcolor()
    {
        return color;
    }
    int getMaxspeed()
    {
        return maxspeed;
    }
    int getModel()
    {
        return model;
    }
    void print()
    {
        cout << "name = " << name << "\n"
            << "color = " << color << "\n"
            << "Maxspeed = " << maxspeed << "\n"
            << "Model = " << model << "\n";
    }

};



int main()
{
    car x;
    x.setName("kia");
    x.setColor("red");
    x.setMaxspeed(300);
    x.setModel(2017);
    x.print();
    return 0;
 
}

Those are the errors I got ( https://i.stack.imgur.com/xTx7E.png )

Answer 1

It's telling you the problem fairly directly. You're trying to pass string literals to setName and setColor . To be compatible with a string literal, you need an argument of type char const * (or equivalently, const char * ). But what you've used is char [] , which (in the case of a function argument) is equivalent to char * .

So, change the arguments to char const * :

void setName(char const *n)
{
    strcpy_s(name, n);
}

Once you've done that, look up std:string , and (unless required for homework or similar) quit using raw pointers to char .

Answer 2

In C++, char* (or char[] , as you wrote it) is a different type than const char* and string literals are of the latter. You can't pass a const char* to a function expecting char* .

If you rewrite your functions to take const char* or const char[] , it'll work:

    void setColor(const char n[])
    // ...
    void setColor(const char n[])
    // ...