[英]Copy python string characters to array.array (to be accessed later from C++)?
How can one copy python string characters to array.array
?如何将 python 字符串字符复制到
array.array
?
from array import array
b = array('b', [0]*30)
s = 'abc'
# What should one do here to copy integer representation of 's' characters to 'b' ?
The integer representation of s
characters should make sense to C++: ie if I convert the integers in b
to C++ char
string, I should get back "abc". s
字符的整数表示对于 C++ 应该有意义:即如果我将b
中的整数转换为 C++ char
字符串,我应该得到“abc”。
The best idea I have is below (but it would be good avoid explicit python loops):我最好的想法如下(但最好避免显式的 python 循环):
for n,c in enumerate(s): b[n] = ord(c)
Thank you very much for your help!非常感谢您的帮助!
try clearing it and filling it again:尝试清除它并再次填充它:
for i in range(29,-1,-1):
b.pop(i)
len0s = 29 - len(s)
s_lst = [*s]+['\0']+[0]*len0s
b.fromlist(s_lst)
should work if s is under 30 characters如果 s 少于 30 个字符应该可以工作
array methods from https://pythongeeks.org/python-array-module/来自https://pythongeeks.org/python-array-module/的数组方法
You can do this if you have the 30-byte array populated ahead of time:如果您提前填充了 30 字节的数组,则可以执行此操作:
b = array('b', bytes(s, 'utf-8') + b[len(s):])
Or if you want to make it from scratch:或者,如果您想从头开始制作:
b = array('b', bytes(s, 'utf-8') + b'\0' * (30 - len(s)))
Or using the struct
module:或者使用
struct
模块:
struct.pack_into('30s', b, 0, bytes(s, 'utf-8'))
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