Javascript Regex 空格之前的所有内容，包括空格

Question

I need to remove all text before a space and the space itself from a list of strings. For example, John Doe needs to be just Doe . How could I do that?

Answer 1

Does it have to be regex? As an option; if you need everything after the space, you can just use split and then pop to get the last item.

var str = 'John Doe';
var final = str.split(' ').pop();
console.log(final);

Here is a solution using a list of string, as you mentioned:

 var strList = ['John Doe', 'Jane Smith', 'Stack Overflow']; for (var i = 0; i < strList.length; i++) { var final = strList[i].split(' ').pop(); console.log(final); }

Answer 2

This pattern would work, but it would only work for first space

[^\s]*\s

Usage: str.replace(/[^\s]*\s/,"")

If you want to support something like "John Doe" Then this pattern would work [^\s]*\s+

 console.log("John Doe".replace(/[^\s]*\s/,"")) //only one first space console.log("John Doe".replace(/[^\s]*\s+/,"")) //many spaces