正则表达式不匹配用 soup.get_text() 抓取的文本

Question

The code below works until:

print(salary_range)

This is the code:

url = "https://nofluffjobs.com/pl/job/c-c-junior-software-developer-vesoftx-wroclaw-n6bgtv5f"
reqs = requests.get(url)
soup = BeautifulSoup(reqs.text, "html.parser")
salaries = soup.find_all("h4", class_="tw-mb-0")
markup2 = str(salaries[0])
soup2 = BeautifulSoup(str(salaries[0]), 'html.parser')

salary_range = soup2.get_text().strip()
print(salary_range) #output: "10 000  – 16 000  PLN"

# error on line below
bottom_salary = re.search(r"^(\d{0,2} ?\d{3})", salary_range).group(1)
print(bottom_salary)

bottom_salary_int = re.sub(" ", "", bottom_salary)
print(bottom_salary_int)

Why doesn't re.search() find any match? I've tried many other regular expressions, but it never finds a match and I always get the error AttributeError: 'NoneType' object has no attribute 'group'

Answer 1

The issue is that the character you think is a space is not actually a space, it is a non-breaking space . Despite looking the same, they are completely different characters. It has the same function of a regular space, but it doesn't count for line wrapping purposes. See this small diagram:

10 000  – 16 000  PLN
  ^   ^^
 NBSP SP  ... same deal here 

To match the non-breaking space instead, specify its hex value, 0xA0 . Like this:

from bs4 import BeautifulSoup
import re
import requests

url = "https://nofluffjobs.com/pl/job/c-c-junior-software-developer-vesoftx-wroclaw-n6bgtv5f"
reqs = requests.get(url)
soup = BeautifulSoup(reqs.text, "html.parser")
salaries = soup.find_all("h4", class_="tw-mb-0")
markup2 = str(salaries[0])
soup2 = BeautifulSoup(str(salaries[0]), 'html.parser')

salary_range = soup2.get_text().strip()
print(salary_range)

bottom_salary = re.search(r"^(\d{0,2}\xa0?\d{3})", salary_range).group(1)
print(bottom_salary)

bottom_salary_int = re.sub(" ", "", bottom_salary)
print(bottom_salary_int)

If you're trying to match a space, but the regular space character doesn't match, then it might be a NBSP instead. You can also tell by the website's source code if it uses   instead of a regular space to encode a NBSP.

Answer 2

Just in addition, if you prefer a less explicit definition of a character ( non-breaking space ), simply change the pattern to (\d+.\d+) or (\d+\s\d+) to get your group, also ^ is not needed in this specific case:

. Matches any character.

re.search(r"(\d+.\d+)", e.get_text()).group(1)

\s Matches any space, tab or newline character.

re.search(r"(\d+\s\d+)", e.get_text()).group(1)

To fix the spacing simply split() and join() :

''.join(re.search(r"(\d+.\d+)", e.get_text()).group(1).split())

Example

import requests, re
from bs4 import BeautifulSoup

url = "https://nofluffjobs.com/pl/job/c-c-junior-software-developer-vesoftx-wroclaw-n6bgtv5f"
reqs = requests.get(url)
soup = BeautifulSoup(reqs.content)
for e in soup.find_all("h4", class_="tw-mb-0"):
    print(''.join(re.search(r"(\d+.\d+)", e.get_text()).group(1).split()))

Output

10000
9000