如何将 a.zip 文件中的多个.txt 文件合并到 Python 中的一个.txt 文件中？

Question

I'm trying to merge multiple.txt files that are in a.zip file into only one.txt file in Python.

My code is the following:

firstfile = Path(r'C:\Users\Viniz\Downloads\devkmbe-5511001_05-12-2022_00_20_09.zip\AudioCaptureMemoryUsage_01_12_2022.txt')
secondfile = Path(r'C:\Users\Viniz\Downloads\devkmbe-5511001_05-12-2022_00_20_09.zip\AudioMatchingMemoryUsage_01_12_2022.txt')

newfile = input("Enter the name of the new file: ")
print()
print("The merged content of the 2 files will be in", newfile)

with open(newfile, "wb") as wfd:
    for f in [firstfile, secondfile]:
        with open(f, "rb") as fd:
            shutil.copyfileobj(fd, wfd, 1024 * 1024 * 10)

print("\nThe content is merged successfully.!")
print("Do you want to view it ? (y / n): ")

check = input()
if check == 'n':
    exit()
else:
    print()
    c = open(newfile, "r")
    print(c.read())
    c.close()

Thanks.

I tried to merge them in only one file but it doesn't worked.

Answer 1

To merge the files, you'll need to first extract the files from the zip file, then merge them, and then write the merged content to a new file. Here is an example of how you can do this using the zipfile module.

Update: If the.txt files are located inside a folder within the zip file, you'll need to include the folder name in the path when opening the files.

import zipfile

zip_file = r'C:\Users\Viniz\Downloads\devkmbe-5511001_05-12-2022_00_20_09.zip'
folder_name = 'myfolder'
first_file = folder_name + '/AudioCaptureMemoryUsage_01_12_2022.txt'
second_file = folder_name + '/AudioMatchingMemoryUsage_01_12_2022.txt'

with zipfile.ZipFile(zip_file, 'r') as zip_ref:
    with zip_ref.open(first_file) as f1, zip_ref.open(second_file) as f2:
        first_content = f1.read()
        second_content = f2.read()

    # Concatenate the two files
    merged_content = first_content + second_content
    
    # Write the merged content to a new file
    new_file = input("Enter the name of the new file: ")
    with open(new_file, 'wb') as new_f:
        new_f.write(merged_content)
        
    print("The content is merged successfully.!")
    print("Do you want to view it ? (y / n): ")

    check = input()
    if check == 'n':
        exit()
    else:
        print()
        c = open(new_file, "r")
        print(c.read())
        c.close()

Make sure to replace 'myfolder' with the actual name of the folder containing the.txt files in your zip file.

For multiple files..

import zipfile

zip_file = r'C:\Users\Viniz\Downloads\devkmbe-5511001_05-12-2022_00_20_09.zip'
folder_name = 'myfolder'
file_names = ['AudioCaptureMemoryUsage_01_12_2022.txt',
              'AudioMatchingMemoryUsage_01_12_2022.txt',
              'File3.txt',
              'File4.txt',
              ...
              'File29.txt']

merged_content = b''  # Initialize an empty bytes object
with zipfile.ZipFile(zip_file, 'r') as zip_ref:
    for file_name in file_names:
        with zip_ref.open(folder_name + '/' + file_name) as f:
            merged_content += f.read()
            
    # Write the merged content to a new file
    new_file = input("Enter the name of the new file: ")
    with open(new_file, 'wb') as new_f:
        new_f.write(merged_content)
        
    print("The content is merged successfully.!")
    print("Do you want to view it ? (y / n): ")

    check = input()
    if check == 'n':
        exit()
    else:
        print()
        c = open(new_file, "r")
        print(c.read())
        c.close()

Answer 2

import os
import zipfile
import shutil

def extract_txt_files(zip_path, temp_folder):
    """Extracts all the .txt files from the given zip file to the given temp folder"""
    with zipfile.ZipFile(zip_path, "r") as zip_file:
        i = len([name for name in os.listdir(temp_folder) if name.endswith(".txt")]) + 1
        for member in zip_file.infolist():
            if member.filename.endswith(".txt"):
                zip_file.extract(member, temp_folder)
                os.rename(os.path.join(temp_folder, member.filename), os.path.join(temp_folder, f"{i}.txt"))
                i += 1

def merge_txt_files(temp_folder):
    """Merges all the .txt files from the given temp folder into a single file called "merged.txt" """
    with open("merged.txt", "w") as outfile:
        for filename in os.listdir(temp_folder):
            if filename.endswith(".txt"):
                with open(os.path.join(temp_folder, filename)) as infile:
                    outfile.write(infile.read())

def delete_temp_folder(temp_folder):
    """Deletes the given temp folder"""
    os.rmdir(temp_folder)

# paths to the zip files
zip1_path = "zip1.zip"
zip2_path = "zip2.zip"

# create a temporary folder to extract the .txt files
temp_folder = "temp"
os.makedirs(temp_folder, exist_ok=True)

# extract the .txt files from the zip files
extract_txt_files(zip1_path, temp_folder)
extract_txt_files(zip2_path, temp_folder)

# merge the .txt files
merge_txt_files(temp_folder)

# delete the temporary folder
shutil.rmtree(temp_folder)


print("The content is merged successfully.!")
    print("Do you want to view it ? (y / n): ")

    check = input()
    if check == 'n':
        exit()
    else:
        print()
        c = open(new_file, "r")
        print(c.read())
        c.close()

The zip path in the script is relative, which means that the zip files "zip1.zip" and "zip2.zip" are expected to be in the same directory as the script.

If the zip files contain multiple.txt files, the script will extract all of them to the temporary folder.

the script renames the extracted.txt files with an incremental index and the.txt extension to ensure that all the extracted files will have unique names and not overwritten.This will maintain the order of txt files as they were in zip file.