如何生成一组由C#中一定位数组成的数字？

Question

I have to generate a set of numbers consisting of 5 digits, as shown below. I tried to search some info about this but found nothing.

int playerId;

System.Random rand = new System.random();
for (int i = 0; i <= 5; i++)
{
     playerId = random.Next();
}
Console.Write($"Generating player ID: {playerId}");

// output example: Generating player ID:  1158453178

As a result, i got a set of numbers consisting of 10 digits. How can i solve this problem?

Answer 1

What you're doing in your code is generating five different random numbers of 10 digits ( random.Next() generates integers less than the integer maximum value, 2147483647) and printing the last one. If you want to generate a 5 digit random number, you can just use random.Next(100000).ToString("D5") , which will generate a random positive integer under 100,000, and then fill out the front with zeroes if needed.

Answer 2

you should put Console.Write($"Generating player ID: {playerId}"); inside the for block, something like this:

int playerId;
System.Random rand = new System.random();
for (int i = 0; i < 5; i++)
 {
  playerId = random.Next();
  Console.Write($"Generating player ID: {playerId}");
 }