C ++中自定义字符串类的<<运算符函数的返回值

Question

I am trying to create my own std::string wrapper to extend its functionality. But I got a problem when declaring the << operator. Here's my code so far:

my custom string class:

class MyCustomString : private std::string
{
public:
  std::string data;
  MyCustomString() { data.assign(""); }
  MyCustomString(char *value) { data.assign(value); }
  void Assign(char *value) { data.assign(value); }
  // ...other useful functions
  std::string & operator << (const MyCustomString &src) { return this->data; }
};

the main program:

int main()
{
  MyCustomString mystring("Hello");
  std::cout << mystring; // error C2243: 'type cast' : conversion from 'MyCustomString *' to 'const std::basic_string<_Elem,_Traits,_Ax> &' exists, but is inaccessible

  return 0;
}

I wanted cout to treat the class as a std::string, so that I won't need to do something like:

std::cout << mystring.data;

Any kind of help would be appreciated!

Thanks.

Just fyi: my IDE is Microsoft Visual C++ 2008 Express Edition.

Answer 1

If you look at how all stream operators are declared they are of the form:

ostream& operator<<(ostream& out, const someType& val );

Essentially you want your overloaded function to actually do the output operation and then return the new updated stream operator. What I would suggest doing is the following, note that this is a global function, not a member of your class:

ostream& operator<< (ostream& out, const MyCustomString& str )
{
    return out << str.data;
}

Note that if your 'data' object was private, which basic OOP says it probably should, you can declare the above operator internally as a 'friend' function. This will allow it to access the private data variable.

Answer 2

You need a free-standing function (friend of your class, if you make your data private as you probably should!)

inline std::ostream & operator<<(std::ostream &o, const MyCustomString&& d)
{
    return o << d.data;
}

Answer 3

That's not how you overload the << operator. You need to pass in a reference to an ostream and return one (so you can stack multiple <<, like std::cout << lol << lol2 ).

ostream& operator << (ostream& os, const MyCustomString& s);

Then just do this:

ostream& operator << (ostream& os, const MyCustomString& s)
{
   return os << s.data;
}

Answer 4

Firstly, you seem to have an issue with the definition of MyCustomString. It inherits privately from std::string as well as containing an instance of std::string itself. I'd remove one or the other.

Assuming you are implementing a new string class and you want to be able to output it using std::cout , you'll need a cast operator to return the string data which std::cout expects:

operator const char *()
{
    return this->data.c_str();
}