[英]How do I query for a max value and return date found
I am trying to query for a maximium value from 5am to 5am the next morning. 我想查询第二天早上5点到5点的最大值。 I would also like to have the start of query date in the results. 我也想在结果中查询日期的开始。
here is what I have so far 这是我到目前为止所拥有的
Select Max(Value) as RWQ22003DTDDS from History
WHERE Datetime>='2009-08-21 05:00:00'
AND Datetime<='2009-08-22 05:00:00' and Tagname ='RWQ22003DTDDS'
I would like the date of "2009-08-21" to be in the results. 我希望日期为“ 2009-08-21”。
datetime, value
------------------
2008-08-21, 2216
2008-08-20, 4312
etc. and to do this for 7 days previous 等等,并在7天内这样做
UPDATE : 更新:
here's another approch I came up with 这是我想到的另一个方法
declare @dec int
declare @SqlQry as varchar(4000)
declare @dd as nvarchar(50)
declare @ResolvedQry as varchar(4000)
set @dec = 0
set @SqlQry =''
WHILE (@dec <= 7)
BEGIN
set @dd = cast(datepart(mm,getdate()-@dec)as nvarchar) +'/'+
cast(datepart(dd,getdate()-@dec)as nvarchar) +'/'+
cast(datepart(yyyy,getdate()-@dec) as nvarchar)+' 06:00:00'
set @ResolvedQry = ' Select cast( convert(datetime,'''+@dd+''',102) as datetime) as [Date],
Max(Value) as RWQ22003DTDDS from History
WHERE Datetime>='''+ convert(varchar, dateadd(mi,5,convert(datetime,@dd,102))) +
''' and Datetime<='''+ convert(varchar, dateadd(mi,-5,convert(datetime,@dd,102)+1)) +'''
and Tagname =''RWQ22003DTDDS'''
if(@dec <7)
begin
set @ResolvedQry =@ResolvedQry + ' union'
end
set @SqlQry = @SqlQry + @ResolvedQry
set @dec = @dec + 1
END
set @SqlQry ='select * from ( ' + @SqlQry + ') as dt order by [Date] desc'
print @SqlQry
exec(@SqlQry)
results: 结果:
Date RWQ22003DTDDS
------------------- ----------------------
Aug 21 2009 5:00AM 3586
Aug 20 2009 5:00AM 7233
Aug 19 2009 5:00AM 9099
Aug 18 2009 5:00AM 9099
Aug 17 2009 5:00AM 8909
Aug 16 2009 5:00AM 8516
Aug 15 2009 5:00AM 8064
Aug 14 2009 5:00AM 7437
Comments? 评论?
try this (assumes that multiple rows are ok, if the YourValue is not a PK): 尝试以下操作(如果YourValue不是PK,则假设多行都可以):
SELECT
YourTable.*
FROM YourTable
INNER JOIN (SELECT
MAX(YourValue) AS YourValue
FROM YourTable
WHERE YourDate>=_StartDateTime
AND YourDate<=_EndDateTime_
) dt ON YourTable.YourValue=dt.YourValue
I solve this kind of query this way: 我通过这种方式解决这种查询:
CREATE TEMPORARY TABLE Timespan (
Start DATETIME,
End DATETIME
);
INSERT INTO Timespan VALUES
('2009-08-21 05:00:00', '2009-08-22 05:00:00'),
('2009-08-20 05:00:00', '2009-08-21 05:00:00'),
('2009-08-19 05:00:00', '2009-08-20 05:00:00'),
('2009-08-18 05:00:00', '2009-08-19 05:00:00'),
('2009-08-17 05:00:00', '2009-08-18 05:00:00'),
('2009-08-16 05:00:00', '2009-08-17 05:00:00'),
('2009-08-15 05:00:00', '2009-08-16 05:00:00');
Select h1.Value as RWQ22003DTDDS, h1.Datetime
FROM Timespan t JOIN History h1 ON
(h1.Datetime BETWEEN t.Start AND t.End AND h1.Tagname = 'RWQ22003DTDDS')
LEFT JOIN History h2 ON
(h2.Datetime BETWEEN t.Start AND t.End AND h2.Tagname = 'RWQ22003DTDDS')
AND (h1.Value < h2.Value OR (h1.Value = h2.Value AND h1.Id < h2.Id))
WHERE h2.Value IS NULL;
Here is a SQL Server solution for what I think you want. 这是我想要的SQL Server解决方案。 It shouldn't be hard to adapt to another dialect of SQL. 适应另一种SQL方言应该不难。
Notes: Because of the LEFT join, there will be a result for days with no History; 注意:由于有LEFT联接,将有几天没有历史记录的结果; I've changed <= to < so that rows where "Datetime" falls at exactly 5:00 am will only be counted in one day. 我已将<=更改为<,以便“日期时间”恰好在上午5:00处的行将仅在一天之内进行计数。
create table Seven(
daysBack int primary key
);
insert into Seven values
(0),(1),(2),(3),(4),(5),(6);
declare @today date = cast(current_timestamp as date);
select
dateadd(day,-daysBack,@today) as QueryDateFrom,
Max(Value) as RWQ22003DTDDS
from Seven left outer join History
on "Datetime" >= dateadd(day,-daysBack,@today)
and "Datetime" < dateadd(day,1-daysBack,@today)
group by dateadd(day,-daysBack,@today)
SELECT CONVERT(CHAR(10), [datetime] ,110) , MAX([value]) SELECT CONVERT(CHAR(10),[datetime],110),MAX([value])
..... .....
GROUP BY CONVERT(CHAR(10), [datetime] ,110) GROUP BY CONVERT(CHAR(10),[datetime],110)
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