Java：从字符串中删除双精度并存储在数组中

Question

I have a string that will be different each time but follow the form of -3.33,-46.53,37.39,26.55,97.11,68.46,-32.46,-5.89,-62.89,-7.9, and i want to remove each number and store as an double in an array. even pseudocode would be great i'm drawing a blank. Cheers

Answer 1

 String[] doubles = myString.split(",");

然后遍历 doubles 数组并执行 Double.parseDouble();

Answer 2

Alternative way, reads input from file and parses items as thy are read.

static java.util.ArrayList<Double> getData(String filename) throws FileNotFoundException {
    java.util.ArrayList<Double> result = new java.util.ArrayList<Double>();
    java.util.Scanner sc = new java.util.Scanner(new java.io.File(filename));

    sc.useDelimiter(",");
    while (sc.hasNext())
        result.add(Double.parseDouble(sc.next()));
    sc.close();

    return result;
}

If you want, you can just store them in a array like:

    Double data[] = null;
    getData("input.dat").toArray(data);

Answer 3

Maybe something like:

String[] sa = yourString.split(",");
Double[] da = new Double[sa.length];
int idx = o;
for(String s : sa) {
   da[idx++] = Double.parseDouble(s); 
}

Answer 4

Split the string based on the ',' and store into a string array.

String[] arr= Str.split(",");

Then make a double array and put the each str values into that double array.

Double[] res= new Double[arr.length];
for(int i=0;i<arr.length;i++){
    res[i] = Double.parseDouble(arr[i]); 
}