[英]Do autoboxing and unboxing behave differently in Java and C#
I am manually converting code from Java (1.6) to C# and finding some difficulty with the behaviour of primitives (int and double). 我手动将代码从Java(1.6)转换为C#,并发现原语(int和double)的行为有些困难。 In C# it appears that almost all conversions happen automatically 在C#中,似乎几乎所有转换都是自动发生的
List<double> list1 = new List<double>(); // legal, C#
double d0 = 3.0;
list1.Add(d0); // legal, C#
Double dd = 2.3f; // legal, C#
list1.Add(dd); // legal, C#
List<Double> list2 = new List<Double>(); // legal, C#
double d1 = 3.0;
list2.Add(d1); // legal, C#
list2.Add(2.0); // legal, C#
double d2 = list2.get(0); // legal, C#
but in Java only some are allowed 但在Java中只允许一些
List<double> list1 = new ArrayList<double>(); // illegal, Java
List<Double> list2 = new ArrayList<Double>(); // legal, Java
double d1 = 3.0;
list2.add(d1); // legal, Java
list2.add(2.0); // legal, Java
double d2 = list2.get(0); // legal, Java
I'd be grateful for a systematic analysis of the differences and any underlying rationale. 我很感激系统分析差异和任何潜在的理由。
In C#, double
and Double
are exactly the same thing (as long as you haven't created your own type called Double
, which would be stupid). 在C#中, double
和Double
完全相同 (只要你没有创建自己的类型Double
,这将是愚蠢的)。
double
is defined as an alias to global::System.Double
. double
被定义为global::System.Double
的别名。 As such, there is no boxing here. 因此,这里没有拳击。
In java, Double
is a boxed double
, with type-erasure being a key part of the generics implementation. 在java中, Double
是一个盒装double
精度型,其中type-erasure是泛型实现的关键部分。
In your C# example there is no boxing or unboxing (and autoboxing) happening. 在您的C#示例中,没有发生装箱或拆箱(和自动装箱)。 double
is just an alias for the struct
Double
. double
只是struct
Double
的别名。
In Java, the boxing is necessary. 在Java中,拳击是必要的。 Because of type erasure , you can't create a List<double>
, only List<Double>
. 由于类型擦除 ,您无法创建List<double>
,只能创建List<Double>
。 At compile time, List<?>
becomes List<Object>
and boxing/unboxing will need to take place so you can add a native type variable to a List<Object>
or assign a native variable to an element of the List. 在编译时, List<?>
变为List<Object>
并且需要进行装箱/取消装箱,因此您可以将本机类型变量添加到List<Object>
或将本机变量分配给List的元素。
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