[英]passing POST array to php function
Can i pass the entire POST array into a function and handle it within the function? 我可以将整个POST数组传递给函数并在函数内处理它吗?
such as 如
PostInfo($_POST);
function PostInfo($_POST){
$item1 = $_POST[0];
$item2 = $_POST[1];
$item3 = $_POST[2];
//do something
return $result;
}
or is this the correct way of doing this? 或者这是正确的方法吗?
Yes. 是。 If you are going to name the local variable
$_POST
though, don't bother. 如果您要命名本地变量
$_POST
,请不要打扰。 $_POST
is a 'superglobal', a global that doesn't require the global
keyword to use it outside normal scope. $_POST
是一个'超全局',一个不需要global
关键字在正常范围之外使用它的global
。 Your above function would work without the parameter on it. 您的上述功能可以在没有参数的情况下工作。
NOTE You cannot use any superglobal (ie
$_POST
) as a function argument in PHP 5.4 or later.注意在PHP 5.4或更高版本中,不能使用任何超全局(即
$_POST
)作为函数参数。 It will generate a Fatal error它会产生致命错误
You can actually pass $_POST to any function which takes in an array. 您实际上可以将$ _POST传递给任何接收数组的函数。
function process(array $request)
{
}
process($_POST);
process($_GET);
Great for testing. 非常适合测试。
The $_POST
-array is an array like every other array in PHP (besides being a so-called superglobal ), so you can pass it as a function parameter, pass it around and even change it (even though this might not be wise in most situations). $_POST
-array是一个像PHP中的每个其他数组一样的数组(除了是一个所谓的超全局 ),所以你可以将它作为函数参数传递,传递它甚至改变它(尽管这可能不是明智的大多数情况)。
Regarding your code, I'd change it a bit to make it more clear: 关于你的代码,我会稍微改变一下以使其更清晰:
PostInfo($_POST);
function PostInfo($postVars)
{
$item1 = $postVars[0];
$item2 = $postVars[1];
$item3 = $postVars[2];
//do something
return $result;
}
This will visibly separate the function argument from the $_POST
superglobal. 这将明显地将函数参数与
$_POST
超全局分开。 Another option would be to simple remove the function argument and rely on the superglobal-abilities of $_POST
: 另一种选择是简单地删除函数参数并依赖
$_POST
的超全局能力:
PostInfo();
function PostInfo()
{
$item1 = $_POST[0];
$item2 = $_POST[1];
$item3 = $_POST[2];
//do something
return $result;
}
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