将帖子数组传递给函数
[英]passing post array to function
问题描述
How can i pass a post array to a functing then pull out the params ie 
我怎样才能将一个发布数组传递给一个函数，然后拉出参数，即
so i am posting the following. 所以我发布以下内容。
url=http%3A%2F%2Fwww.facebook.com%2Ftest&userId=680410999&location=Cardiff&lang=en_US&social=facebook
can i grab it like this from the function???? 我可以从功能中像这样抓住它吗？
function login($_POST){
//then output the var her.
$_POST['url']; etc
}
this is to save me doing the following in my ajax.php file 这是为了节省我在ajax.php文件中执行以下操作的过程
function login($_POST['url'],$_POST['userId'],$_POST['location'],$_POST['lang']){
}
any help pls 任何帮助
4 个解决方案
解决方案1
4 2011-12-08 15:43:59
First you should use $_GET and not $_POST . 首先，您应该使用$_GET而不是$_POST 。 Second you don't need to call your function parameter as $_GET . 其次，您不需要将函数参数称为$_GET 。 You can do this: 你可以这样做：
function login($array)
{
// do stuff with array
}
and then call the function in this way: 然后以这种方式调用该函数：
login($_GET);
An additional suggest is to read the following quote and that is the difference of actual parameters towards formal parameters : 另一个建议是阅读以下引用，这是实际参数与形式参数的区别：
Formal parameters are the parameters as they are known in the function definition.
解决方案2
0 2011-12-08 15:49:13
If I unserstand you correctly you want a function that you call and pass it an array (in your case the $_POST or $_GET array) as a parameter. 如果我对您的理解不正确，则需要一个函数，然后将其作为参数传递给数组（在您的情况下为$_POST或$_GET数组）。
So your function would look something like this: 因此，您的函数将如下所示：
// not sure what you're doing with your login options but here's an example of getting them out of the array and putting them in variables - using the url as an example here...
var url;
function login($loginOptions) {
// set the url from the array
url = $loginOptions["url"];
// do the same for all your other variable...
}
Then you would call your function like so: 然后，您将这样调用函数：
login($_POST); // or $_login($_GET); depending on what you're using
And that's it! 就是这样！
解决方案3
0 2011-12-08 15:49:40
The other answers you have got should solve this problem for you. 您得到的其他答案应该可以为您解决此问题。
Just some more advice, remember to clean any $_POST and $_GET data that you are using in your code. 仅提供一些建议，请记住清除代码中使用的所有$_POST和$_GET数据。
For example, if you are using it in a database query then you will need to use mysql_real_escape_string(); 例如，如果在数据库查询中使用它，则将需要使用mysql_real_escape_string(); and if you are echo'ing the data then use htmlentities(); 如果回显数据，则使用htmlentities();
解决方案4
0
I think what you mean is parsing array to a function for this I will tell you to use a function and connected it with SESSION as this below. 我认为您的意思是为此将数组解析为函数，我将告诉您使用函数并将其与SESSION连接，如下所示。 You can use the $_GET[$var] to retrieve the variable but it's quite hard to be handled by the method get, you can use the method $_POST and combine it with session to save the data , I will explain how to collaborate the session each page so that you can easily retrieve the variable you wanted. 您可以使用$ _GET [$ var]来检索变量，但是get方法很难处理，可以使用$ _POST方法并将其与会话结合起来以保存数据，我将说明如何协作对每个页面进行会话，以便您可以轻松检索所需的变量。 Here's the code : 这是代码：
<?php
session_start();
if(isset ($_POST['postedit']))
{
$_SESSION['url'] = $_POST['urlsend'];
header("location:dua.php");
}
?>
<html>
<body>
<form action="satu.php" method="POST">
Name : <input type="text" name="urlsend"> <br> <br>
<input type="submit" name="postedit" value="SEND DATA">
</form>
</body>
</html>
<?php
session_start();
if(isset ($_SESSION['url']))
{
//if data empty then will be redirected to the previous page
echo $_SESSION['url'];
}
?>
I created with dynamic data even you can choose to use this method or other method. 我创建的都是动态数据，即使您可以选择使用此方法还是其他方法。 I hope you can understand. 我希望你能够明白。
声明:本站的技术帖子网页，遵循CC BY-SA 4.0协议，如果您需要转载，请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.