[英]Adjusting Timezone - Convert XML DateTime to SQL DateTime
We are using TypedDataSet in our application. 我们在应用程序中使用TypedDataSet。 Data is passed to procedure in form of XML for insert/update.
数据以XML的形式传递给过程以进行插入/更新。
Now after populating DE with data, datetime remains the same though timezone information is added as below. 现在,在用数据填充DE之后,尽管添加了以下时区信息,但datetime仍然相同。
Date in DB: 2009-10-29 18:52:53.43 Date in XML: 2009-10-29T18:52:53.43-05:00 DB中的日期:2009-10-29 18:52:53.43 XML中的日期:2009-10-29T18:52:53.43-05:00
Now when I am trying to convert below XML to SQL DateTime it is adjusting 5 hours and I am getting 现在,当我尝试将以下XML转换为SQL DateTime时,它正在调整5个小时,
2009-10-29 23:52:53.430 as the final output, which is wrong. 2009-10-29 23:52:53.430作为最终输出,这是错误的。 Need to find a way to extract datetime from below XML snippet ignoring timezone.
需要找到一种从下面的XML代码片段中提取datetime的方法,而忽略时区。
I have XML in following format, with timezone difference -05.00 我有以下格式的XML,时区不同-05.00
<Order>
<EnteredDateTime>2009-10-29T18:52:53.43-05:00</EnteredDateTime>
</Order>
First convert into typed xsd date time and then use the value method to convert that value to a sql datetime. 首先将其转换为键入的xsd日期时间,然后使用value方法将该值转换为sql datetime。
select convert(xml, '<DateTimeWithTimeZone>2012-09-15T16:08:14.787-05:00</DateTimeWithTimeZone>').value('xs:dateTime(/DateTimeWithTimeZone[1])', 'datetime')
Convert datetime with time zone to SQL datetime 将带时区的datetime转换为SQL datetime
sorry for simply forwarding with an external link, but i found this resource useful recently and always favour authoritative info. 很抱歉仅通过外部链接进行转发,但我最近发现此资源很有用,并且始终偏爱权威信息。
Coding Best Practices Using DateTime in the .NET Framework 在.NET Framework中使用DateTime编码最佳实践
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.