如何将十进制数转换为64位二进制浮点数？

Question

I need to convert decimal number into 64 bit binary float value. If you know any algorithm or anything about it then please help.

Answer 1

使用boost :: lexical_cast 。

double num = lexical_cast<double>(decimal);

Answer 2

Assuming you mean a decimal stored inside a string, atof would be a standard solution to convert that to a double value (which is a 64-bit floating point number on the x86 architecture).

std::string s = "0.4";
double convertedValue = atof(s.c_str());

Or similar for C strings:

const char *s = "0.4";
double convertedValue = atof(s);

But if you mean integer number by "decimal number", then just write

int yourNumber = 100;
double convertedValue = yourNumber;

and the value will automatically be converted.

Answer 3

Value casting from a string to double can be implemented by boost::lexical_cast. Type casting from int to double is a part of C++:

double d = (double)i;

It was already mentioned in the previous replies.

If you are interested to know how this casting is implemented, you may refer the sources of the C standard library your compiler is using given that the sources are provided and no floating point co-processor is used for this purpose. Many embedded target compilers do this work "manually" if no floating point co-processor is available.

For the binary format description, please see Victor's reply

Answer 4

Decimal decimalNumber = 1234;
Float binaryFloatValue = decimalNumber;