将十进制数转换为64位浮点双精度二进制数？

Question

So Ive got a code (from another thread) to convert decimal into floating point binary, problem is its still in 32-bit.

#include <iostream>
#include <bitset>
using namespace std;
int main() {
    union {
        float input;   
        int output;
        }  data;
    float x;
    cin>>x;
    data.input = x;

    bitset<sizeof(float) * CHAR_BIT>   bits(data.output); 
    cout << bits << endl;
  }

how do i change it into a 64-bit floating point binary?

Answer 1

template< std::size_t N >
class bitset;

This is how bitset Defined in header file. So if you want 64 bit. Just type 64 inside the bitset. bitset<64> will give you 64 bit output for your desired input.

Here is the modified code:

#include <iostream>
#include <bits/stdc++.h>
#include <bitset>
using namespace std;
int main() {
    union {
        float input;   
        int output;
        }  data;
    float x;
    cin>>x;
    data.input = x;

    bitset<64>   bits(data.output); 
    cout << bits << endl;
}

Input

2.25125

Output:

0000000000000000000000000000000001000000000100000001010001111011

Online compiler link : http://cpp.sh/832cr