[英]PHP: DomElement->getAttribute
How can I take all the attribute of an element?如何获取元素的所有属性? Like on my example below I can only get one at a time, I want to pull out all of the anchor tag's attribute.
就像在下面的示例中,我一次只能获取一个,我想提取所有锚标记的属性。
$dom = new DOMDocument();
@$dom->loadHTML(http://www.example.com);
$a = $dom->getElementsByTagName("a");
echo $a->getAttribute('href');
thanks!谢谢!
$length = $a->attributes->length;
$attrs = array();
for ($i = 0; $i < $length; ++$i) {
$name = $a->attributes->item($i)->name;
$value = $a->getAttribute($name);
$attrs[$name] = $value;
}
print_r($attrs);
"Inspired" by Simon's answer.受西蒙的回答“启发”。 I think you can cut out the
getAttribute
call, so here's a solution without it:我认为你可以
getAttribute
调用,所以这里有一个没有它的解决方案:
$attrs = array();
for ($i = 0; $i < $a->attributes->length; ++$i) {
$node = $a->attributes->item($i);
$attrs[$node->nodeName] = $node->nodeValue;
}
var_dump($attrs);
$a = $dom->getElementsByTagName("a");
foreach($a as $element)
{
echo $element->getAttribute('href');
}
$html = $data['html'];
if(!empty($html)){
$doc = new DOMDocument();
$doc->loadHTML($html);
$doc->saveHTML();
$datadom = $doc->getElementsByTagName("input");
foreach($datadom as $element)
{
$class =$class." ".$element->getAttribute('class');
}
}
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