在java中比较二维整数数组的最佳方法

Question

I would like to know what is the best, fastest and easiest way to compare between 2-dimension arrays of integer. the length of arrays is the same. (one of the array's is temporary array)

Answer 1

Edan wrote:

just need to see if the value is the same

If you want to check that a[i][j] equals b[i][j] for all elements, just use Arrays.deepEquals(a, b) .

Answer 2

Look at java.util.Arrays ; it has many array utilities that you should familiarize yourself with.

import java.util.Arrays;

int[][] arr1;
int[][] arr2;
//...
if (Arrays.deepEquals(arr1, arr2)) //...

From the API :

Returns true if the two specified arrays are deeply equal to one another. Unlike the equals(Object[],Object[]) method, this method is appropriate for use with nested arrays of arbitrary depth.

Note that in Java, int[][] is a subtype of Object[] . Java doesn't really have true two dimensional arrays. It has array of arrays.

The difference between equals and deepEquals for nested arrays is shown here (note that by default Java initializes int arrays with zeroes as elements).

    import java.util.Arrays;
    //...

    System.out.println((new int[1]).equals(new int[1]));
    // prints "false"

    System.out.println(Arrays.equals(
        new int[1],
        new int[1]
    )); // prints "true"
    // invoked equals(int[], int[]) overload

    System.out.println(Arrays.equals(
        new int[1][1],
        new int[1][1]
    )); // prints "false"
    // invoked equals(Object[], Object[]) overload

    System.out.println(Arrays.deepEquals(
        new int[1][1],
        new int[1][1]
    )); // prints "true"

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