如何为多个类型创建XML序列化器？

Question

I am using the XmlSerializer like this,

XmlSerializer xs = new XmlSerializer(typeof(myType));

Now I have 5 different "myType". How do I pass the specific type dynamically so I don't have to repeat the same code 5 times?

Answer 1

Try XmlSerializer xs = new XmlSerializer(obj.GetType()); .

Answer 2

typeof(myType) will not compile unless myType is a type.

If you have an instance of the type, you can do instance.GetType();

There is not other option im afraid. You have to specify some type compile time anyway.

Answer 3

Another option is to have a generic method. Consider this example:

static T DeserializeObject<T>(XmlReader reader)
{
    XmlSerializer serializer = new XmlSerializer(typeof(T));
    T t = (T)serializer.Deserialize(reader);
    return t;
}

Using it:

static void Main()
{
    string xml = "<Foo><Blah>Hello World</Blah></Foo>";

    using (MemoryStream stream = new MemoryStream(Encoding.Default.GetBytes(xml)))
    {
        XmlReader reader = XmlReader.Create(stream);
        Foo foo = DeserializeObject<Foo>(reader);

        Console.WriteLine(foo.Blah);
    }
}

Answer 4

Just create a little function and have the parameter be of type 'Type'.

    private void SerializeType(Type theType)
    {
        XmlSerializer xs = new XmlSerializer(theType);
    }