Scala返回类型为元组函数

Question

I want to make a scala function which returns a scala tuple.

I can do a function like this:

def foo = (1,"hello","world")

and this will work fine, but now I want to tell the compiler what I expect to be returned from the function instead of using the built in type inference (after all, I have no idea what a (1,"hello","world") is).

Answer 1

def foo : (Int, String, String) = (1, "Hello", "World")

编译器将类型(Int, String, String)为Tuple3[Int, String, String]

Answer 2

Also, you can create a type alias if you get tired of writing (Int,String,String)

type HelloWorld = (Int,String,String)
...

def foo : HelloWorld = (1, "Hello", "World")
/// and even this is you want to make it more OOish
def bar : HelloWorld = HelloWorld(1, "Hello", "World")