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Erlang:如何从其他节点的节点()中删除节点?

[英]Erlang: How can I remove a node from other nodes' nodes()?

I want to simulate the behavior of erl -sname example -hidden but dynamically. 我想模拟erl -sname example -hidden但是动态的行为。 How can I drop a node out of visibility in a cluster? 如何在群集中删除节点的可见性?

See the comments by @mwt at @Yasir Arsanukaev for additional clarification of what I'm trying to do. 请参阅@mwt在@Yasir Arsanukaev的评论,以进一步澄清我正在尝试做什么。

Try erlang:disconnect_node/1 : 试试erlang:disconnect_node/1

(bar@dt)1> nodes().
[]
(bar@dt)2> net_adm:ping('foo@dt').          
pong
(bar@dt)3> nodes().               
[foo@dt]
(bar@dt)4> erlang:disconnect_node('foo@dt').
true
(bar@dt)5> nodes().                         
[]

Or if you want a node to remove itself from other nodes' nodes() : 或者,如果您希望节点从其他节点的nodes()删除自己:

(bar@dt)1> nodes().
[foo@dt]
(bar@dt)2> rpc:eval_everywhere(erlang, disconnect_node, [node()]).
abcast
(bar@dt)3> nodes().
[]

If the node was started with key -hidden : 如果使用密钥-hidden启动节点:

(bar@dt)1> nodes(hidden).
[foo@dt]
(bar@dt)2> rpc:eval_everywhere(nodes(hidden), erlang, disconnect_node, [node()]).
abcast
(bar@dt)3> nodes(hidden).
[]

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