如何分类地图 <Key, Value> Java与谷歌集合排序功能中的值

Question

如果B是一个类，且其字段类型为double，则应使用google collections排序函数对Java中的值对map（？，B）进行排序。

Answer 1

Here's a snippet that uses a generic method that takes a Map<K,V> and a Comparator<? super V> Comparator<? super V> , and returns a SortedSet of its entrySet() sorted on the values using the comparator.

public class MapSort {
    static <K,V> SortedSet<Map.Entry<K,V>>
    entriesSortedByValues(Map<K,V> map, final Comparator<? super V> comp) {
        SortedSet<Map.Entry<K,V>> sortedEntries = new TreeSet<Map.Entry<K,V>>(
            new Comparator<Map.Entry<K,V>>() {
                @Override public int compare(Entry<K, V> e1, Entry<K, V> e2) {
                    return comp.compare(e1.getValue(), e2.getValue());
                }

            }
        );
        sortedEntries.addAll(map.entrySet());
        return sortedEntries;
    }
    static class Custom {
        final double d;   Custom(double d) { this.d = d; }
        @Override public String toString() { return String.valueOf(d); }
    }
    public static void main(String[] args) {
        Map<String,Custom> map = new HashMap<String,Custom>();
        map.put("A", new Custom(1));
        map.put("B", new Custom(4));
        map.put("C", new Custom(2));
        map.put("D", new Custom(3));
        System.out.println(
            entriesSortedByValues(map, new Comparator<Custom>() {
                @Override public int compare(Custom c1, Custom c2) {
                    return Double.compare(c1.d, c2.d);
                }           
            })
        ); // prints "[A=1.0, C=2.0, D=3.0, B=4.0]"
    }
}

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On Google Ordering

public static <T> Ordering<T> from(Comparator<T> comparator)

Returns an ordering for a pre-existing comparator.

The above solution uses a Comparator , so you can easily use the above method to use Ordering instead.

Answer 2

Collections.sort(map.values(), myComparator); Create myComparator as Comparator to compare the B objects by the double field.