Haskell - 如何投射类型？

Question

I am trying to do following:

10 ** length xs * x

but I get:

No instance for (Floating Int) arising from a use of `**'

Answer 1

You can use ^ to raise to an integral power. There's no need to convert to float here.

Answer 2

Besides @sepp2k's answer , if you somehow really need to convert from an integer to some other types of Num, use fromIntegral .

-- # fromIntegral :: (Integral a, Num b) => a -> b

10 ** fromIntegral (length xs) * x