24位图像中有多少种颜色组合

Question

I am reading a book and I am not sure if its a mistake or I am misunderstanding the quote. It reads...

Nowadays every PC you can buy has hardware that can render images with at least 16.7 million individual colors. Rather than have an array with thousands of color entries, the images instead contain explicit color values for each pixel. A 24-bit display, of course, uses 24 bits, or 3 bytes per pixel, for color information. This gives 1 byte, or 256 distinct values each, for red, green, and blue. This is generally called true color, because 256^3 (16.7 million)

He says 1 byte is equal to 256 distinct values. 1 byte = 8 bits. 8^2 bits = 64 combinations of colors right ?? It's not adding up right to me. I know it might be something simple to understand, but I don't understand.

Answer 1

The combinations of 8 bits is not 8 ² (64) but 2 ⁸ (256). This is because each of the 8 bits can have 2 distinct values. For 1 bit that would give you 2 (2 ¹ ) possibilities, for 2 bits 2*2 (2 ² ), for 3 bits 2*2*2 (2 ³ )... etc. 3 bytes = 24 bits => 2 ²⁴ = 16.7M possible combinations.

Answer 2

1 byte = 8 bits = 2^8 = 256 combinations :)

24 bit combinations = 2^24 = Three 8 bit colors = 256^3 = 16777216 ~= 16.7 million color combinations

Answer 3

如果您有24位颜色信息，您可以显示2 ^ 24种颜色= 1670万！