[英]Template object as static member of the template class
Imagine the following template class (setter and getter for the member _t
omitted): 想象以下模板类(省略了成员
_t
setter和getter):
template<class T>
class chain
{
public:
static chain<T> NONE;
chain()
: _next(&NONE)
{}
~chain() {}
chain<T>& getNext() const
{
return *_next;
}
void setNext(chain<T>* next)
{
if(next && next != this)
_next = next;
}
chain<T>& getLast() const
{
if (_next == &NONE)
return *this;
else
return _next->getLast();
}
private:
T _t;
chain<T>* _next;
};
The basic idea of this concept is, instead of using null-pointers, I have a static default element that takes in this role while still being a technically valid object; 这个概念的基本思想是,我没有使用空指针,而是拥有一个静态的默认元素,该元素在保持技术上有效的同时担当了这个角色。 this could prevent some of the issues with null pointers while making the code more verbose at the same time...
这可以防止空指针的某些问题,同时使代码更冗长...
I can instantiate this template just fine, but the linker gives an unresolved-external error on the static member object NONE
. 我可以很好地实例化此模板,但是链接器在静态成员对象
NONE
上给出了一个未解决的外部错误。
I would have assumed that when instantiating the template, the line static chain<T> NONE
; 我本来以为在实例化模板时,行
static chain<T> NONE
; would effectively be a definition, too, as it actually happens within the implementation instantiating the template. 它实际上也将是一个定义,因为它实际上发生在实例化模板的实现中。 However, it turns out not to be...
然而,事实证明不是...
My question is: is something like possible at all, and if so, how, without explicitly defining the NONE
element before each and every template instantiation? 我的问题是:是否有可能实现所有目标?如果没有,在没有每个模板实例化之前都明确定义
NONE
元素的情况下,如何实现?
You still need to define that outside the class just like a non-template class. 您仍然需要像非模板类一样在类外部定义它。 Just like in a non-template class, you have only declared
NONE
inside the class definition and still need to define it: 就像在非模板类中一样,您仅在类定义内声明了
NONE
,但仍然需要对其进行定义:
template<class T>
class chain
{
// the same as your example
};
// Just add this
template <class T>
chain<T> chain<T>::NONE;
template < typename T >
chain<T> chain<T>::NONE;
should work 应该管用
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