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这个简单的boost :: spirit :: qi解析器有什么问题?

[英]What is the problem with this simple boost::spirit::qi parser?

I've got this simple parser intended to parse VB style double quoted strings. 我有这个简单的解析器,用于解析VB样式双引号字符串。 Thus, the parser should turn something like 因此,解析器应该将类似

"This is a quoted string containing quotes ("" "")"

into an output of 变成

This is a quoted string containing quotes (" ")

Here is the grammar I came up with for this: 这是我为此想到的语法:

namespace qi = boost::spirit::qi;
namespace wide = qi::standard_wide;
class ConfigurationParser : public qi::grammar<std::wstring::iterator, std::wstring()>
{
    qi::rule<std::wstring::iterator, std::wstring()> quotedString;
    qi::rule<std::wstring::iterator> doubleQuote;

public:
    ConfigurationParser() : ConfigurationParser::base_type(quotedString, "vFind Command Line")
    {
        doubleQuote = (wide::char_(L'"') >> wide::char_(L'"'));

        quotedString = L'"' >> +(doubleQuote[qi::_val = L'"'] | (wide::char_ - L'"'))>> L'"';
    }
};

However, the attribute I'm getting is a single quote mark ("), rather than the full parsed message. 但是,我得到的属性是单引号(“),而不是完整的解析消息。

You can do it without any semantic actions: 您可以执行此操作而无需任何语义动作:

class ConfigurationParser 
  : public qi::grammar<std::wstring::iterator, std::wstring()> 
{ 
    qi::rule<std::wstring::iterator, std::wstring()> quotedString; 
    qi::rule<std::wstring::iterator, wchar_t()> doubleQuote; 

public: 
    ConfigurationParser() 
      : ConfigurationParser::base_type(quotedString, "vFind Command Line") 
    { 
        doubleQuote = wide::char_(L'"') >> omit[wide::char_(L'"')]; 
        quotedString = L'"' >> +(doubleQuote | (wide::char_ - L'"')) >> L'"'; 
    } 
}; 

The omit[] directive still executes the embedded parser but doesn't expose any attribute, making the doubleQuote rule return a single L'"' . omit[]指令仍执行嵌入式解析器,但不公开任何属性,从而使doubleQuote规则返回单个L'"'

I think you don't save the result properly: 我认为您没有正确保存结果:

doubleQuote[qi::_val = L'"']

Here, because of the '=' sign, you override what was already in. Try with '+=' instead. 在这里,由于有'='符号,您将覆盖已存在的内容。请改用'+ ='。

doubleQuote[qi::_val += L'"']

Also, I don't know if saving is automatic, you may have to add the same '+=' after the other parser in the alternative: 另外,我不知道保存是否是自动的,您可能必须在另一个解析器之后添加相同的“ + =”:

(wide::char_ - L'"')[qi::_val += boost::spirit::arg_names::_1]

But I am not that good with Qi so perhaps it IS automated, which would make sense. 但是我对Qi并不满意,所以也许它是自动化的,这很有意义。

Well, I'm not entirely sure why, but I was able to fix it by moving that assignment action into the sub rule: 好吧,我不确定为什么,但是我可以通过将赋值操作移到子规则中来解决它:

doubleQuote %= (wide::char_(L'"') >> L'"')[qi::_val = L'"'];
doubleQuote.name("double quote");

quotedString = L'"' >> +(doubleQuote | (wide::char_ - L'"')) >> L'"';
quotedString.name("quoted string");

Note the use of operator %= for doubleQuote and the fact that the semantic action is now located there. 注意,对doubleQuote使用了operator %= ,并且语义动作现在位于该位置。

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