最有效的方法来计算Python列表中的值的频率？

Question

I am looking for a fast and efficient way to calculate the frequency of list items in python:

list = ['a','b','a','b', ......]

I want a frequency counter which would give me an output like this:

 [ ('a', 10),('b', 8) ...]

The items should be arranged in descending order of frequency as shown above.

Answer 1

Python2.7+

>>> from collections import Counter
>>> L=['a','b','a','b']
>>> print(Counter(L))
Counter({'a': 2, 'b': 2})
>>> print(Counter(L).items())
dict_items([('a', 2), ('b', 2)])

python2.5/2.6

>>> from collections import defaultdict
>>> L=['a','b','a','b']
>>> d=defaultdict(int)
>>> for item in L:
>>>     d[item]+=1
>>>     
>>> print d
defaultdict(<type 'int'>, {'a': 2, 'b': 2})
>>> print d.items()
[('a', 2), ('b', 2)]