从web.xml文件中获取显示名称

Question

I am trying to get the Display name (Context Root) from web.xml file to avoid hardcoding a context root.

Any help would be appreciated.

Answer 1

ServletContext.getServletContextName()

通过display-name元素返回此Web应用程序的部署描述符中指定的此ServletContext对应的Web应用程序的名称。

Answer 2

There's some ambiguity in your question. The "display name" is not the same as "context root". To get the <display-name> value from web.xml , look at skaffman's answer in this question. To get the <Context path> value from context.xml , use ServletContext#getContextPath() . This is often referenced as "context root" (which you also see in the URL, that part immediately after domain).

Answer 3

En nombre puede obtener de la clase ServletContext. Con JSF

ExternalContext externalContext = FacesContext.getCurrentInstance().getExternalContext();
ServletContext servletContext= (ServletContext) externalContext.getContext();
System.out.println("Context Name: "+servletContext.getServletContextName());

Or Within a Servlet

protected void doGet(HttpServletRequest request, HttpServletResponse response)
{
ServletContext servletContext= getServletContext();
System.out.println("Context Name: "+servletContext.getServletContextName());
}