在Python中模拟C＃的sbyte（8位有符号整数）转换

Question

In C#, I can cast things to 8bit signed ints like so:

(sbyte)arg1;

which when arg1 = 2 , the cast returns 2 also. However, obviously casting 128 will return -128 . More specifically casting 251 will return -5 .

What's the best way to emulate this behavior?

Edit: Found a duplicate question: Typecasting in Python

s8 = (i + 2**7) % 2**8 - 2**7      // convert to signed 8-bit

Answer 1

With ctypes:

from ctypes import cast, pointer, c_int32, c_byte, POINTER
cast(pointer(c_int32(arg1)), POINTER(c_byte)).contents.value

Answer 2

I'd use the struct module of the Python standard library, which, as so often, comes in handy for turning values into bytes and viceversa:

>>> def cast_sbyte(anint):
    return struct.unpack('b', struct.pack('<i', anint)[0])[0]
... ... 
>>> cast_sbyte(251)
-5

Answer 3

struct module can help you, eg here is a way to convert int(4 bytes) to 4 signed bytes

>>> import struct
>>> struct.pack('i',251)
'\xfb\x00\x00\x00'
>>> s=struct.pack('i',251)
>>> print struct.unpack('bbbb',s)
(-5, 0, 0, 0)

Answer 4

>>> from numpy import int8
>>> int8(251)
-5

Answer 5

Try one of the following:

>>> sbyte=lambda n:(255 & n^128)-128 
>>> # or sbyte=lambda n:(n+128 & 255)-128

>>> sbyte(251)
-5
>>> sbyte(2)
2