简体   繁体   English

TypeError使用BOTO Library将图像文件上传到Django中的Amazon S3

[英]TypeError uploading image file to Amazon S3 in Django using BOTO Library

I am a total beginner to programming and Django so I'd appreciate help that beginner can get his head round! 我是编程和Django的初学者,所以我很感激帮助初学者可以得到他的头脑!

I was following a tutorial to show how to upload images to an Amazon S3 account with the Boto library but I think it is for an older version of Django (I'm on 1.1.2 and Python 2.65) and something has changed. 我正在按照一个教程来展示如何使用Boto库将图像上传到Amazon S3帐户,但我认为它适用于较旧版本的Django(我在1.1.2和Python 2.65)并且有些变化。 I get an error: Exception Type: TypeError Exception Value: 'InMemoryUploadedFile' object is unsubscriptable 我收到一个错误:异常类型:TypeError异常值:'InMemoryUploadedFile'对象是unsubscriptable

My code is: 我的代码是:

Models.py: Models.py:

from django.db import models
from django.contrib.auth.models import User
from django import forms
from datetime import datetime

class PhotoUrl(models.Model):
    url = models.CharField(max_length=128)
    uploaded = models.DateTimeField()
    def save(self):
        self.uploaded = datetime.now()
        models.Model.save(self)

views.py: views.py:

import mimetypes
from django.http import HttpResponseRedirect
from django.shortcuts import render_to_response
from django.core.urlresolvers import reverse
from django import forms
from django.conf import settings
from boto.s3.connection import S3Connection
from boto.s3.key import Key

def awsdemo(request):   
def store_in_s3(filename, content):
    conn = S3Connection(settings.AWS_ACCESS_KEY_ID, settings.AWS_SECRET_ACCESS_KEY)
    b = conn.create_bucket('almacmillan-hark')
    mime = mimetypes.guess_type(filename)[0]
    k = Key(b)
    k.key = filename
    k.set_metadata("Content-Type", mime)
    k.set_contents_from_strong(content)
    k.set_acl("public-read")

photos = PhotoUrl.objects.all().order_by("-uploaded")
if not request.method == "POST":
    f = UploadForm()
    return render_to_response('awsdemo.html', {'form':f, 'photos':photos})

f = UploadForm(request.POST, request.FILES)
if not f.is_valid():
    return render_to_response('awsdemo.html', {'form':f, 'photos':photos})

file = request.FILES['file']
filename = file.name
content = file['content']
store_in_s3(filename, content)
p = PhotoUrl(url="http://almacmillan-hark.s3.amazonaws.com/" + filename)
p.save()
photos = PhotoUrl.objects.all().order_by("-uploaded")   
return render_to_response('awsdemo.html', {'form':f, 'photos':photos})

urls.py: urls.py:

(r'^awsdemo/$', 'harkproject.s3app.views.awsdemo'), 

awsdemo.html: awsdemo.html:

<div class="form">
    <strong>{{form.file.label}}</strong>
    <form method="POST" action ="." enctype="multipart/form-data">
        {{form.file}}<br/>
        <input type="submit" value="Upload">
    </form> 
</div>  

I'd really appreciate help. 我真的很感激帮助。 I hope I have provided enough code. 我希望我提供了足够的代码。

Kind regards AL 亲切的问候AL

I think your problem is this line: 我认为你的问题是这一行:

content = file['content']

From the Django docs : 来自Django文档

Each value in FILES is an UploadedFile object containing the following attributes: FILES中的每个值都是一个UploadedFile对象,包含以下属性:

  • read(num_bytes=None) -- Read a number of bytes from the file. read(num_bytes = None) - 从文件中读取一些字节。
  • name -- The name of the uploaded file. name - 上载文件的名称。
  • size -- The size, in bytes, of the uploaded file. size - 上载文件的大小(以字节为单位)。
  • chunks(chunk_size=None) -- A generator that yields sequential chunks of data. chunk(chunk_size = None) - 生成顺序数据块的生成器。

Try this instead: 试试这个:

content = file.read()

Have you tried Django Storages ? 你试过Django存储吗? That way you only have to specify a storage backend (s3boto in this case) either as the default storage backend, or supply it as an argument to a FileField or ImageField class. 这样,您只需将存储后端(在本例中为s3boto)指定为默认存储后端,或将其作为参数提供给FileField或ImageField类。

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM