C ++进程启动路径问题

Question

I'm using process::start(PATH); to open up the process. The problem is, sometimes it finds the file and sometimes it doesn't.

For example, this works:

process::start("C:\text.exe");

But this doesn't work:

process::start("C:\New Folder\text.exe");

Any idea what the difference is?

Answer 1

You have to escape the \\ characters.

In a C string \\t is the TAB character. Use:

process::start("C:\\New Folder\\text.exe");

Answer 2

The library might think that c:\\New is the program you are running, and Folder\\text.exe is an argument you are passing to it.

You might need to quote it, so you're calling this:

"C:\New Folder\text.exe"

Which as a C++ string would look like this:

process::start("\"C:\\New Folder\\text.exe\"");