具有多个目标的 Makefile

Question

Hopefully this is a very simple question. I have a makefile pattern rule that looks like this:

%.so : %.f %.pyf
    f2py -c -L${LAPACK_DIR} ${GRASPLIBS} -m $* $^ ${SOURCES} --opt='-02' --f77flags='-fcray-pointer' >> silent.txt

I want the makefile to build a number of .so files, so I tried to get it to build two files (radgrd_py.so and lodiso_py.so) by doing this:

radgrd_py.so lodiso_py.so:

%.so : %.f %.pyf
f2py -c -L${LAPACK_DIR} ${GRASPLIBS} -m $* $^ ${SOURCES} --opt='-02' --f77flags='-fcray-pointer' >> silent.txt

and then tried this:

radgrd_py.so:

lodiso_py.so:

%.so : %.f %.pyf
f2py -c -L${LAPACK_DIR} ${GRASPLIBS} -m $* $^ ${SOURCES} --opt='-02' --f77flags='-fcray-pointer' >> silent.txt

But in each case, it only builds the first target that I specify. If I run 'make radgrd_py.so' it works fine, I'm just not sure how to specify a list of files that need to be built so I can just run 'make'.

Answer 1

The usual trick is to add a 'dummy' target as the first that depends on all targets you want to build when running a plain make :

all: radgrd_py.so lodiso_py.so

It is a convention to call this target 'all' or 'default'. For extra correctness, let make know that this is not a real file by adding this line to your Makefile :

.PHONY: all

Answer 2

Best way is to add:

.PHONY: all
.DEFAULT: all
all: radgrd_py.so lodiso_py.so

Explanations:

make uses the first target appearing when no .DEFAULT is specified.

.PHONY informs make that the targets (a coma-separated list, in fact) don't create any file or folder.

all: as proposed by schot