从命令获取 GNU makefile 目标

Question

I use the following code to get a makefile targets list which works OK for most cases, however when you use makefile like this you get only two targets and not all.

cat Makefile

command: ## Command description
    @echo "Execution log"

another-command: ## Command description
    @echo "Execution log"

command2: ## Command description
    @echo "Execution log" 

The output is:

command
command2

I don't understand why I don't getting the command another-command , This is the code

`make -qp | awk -F':' '/^[a-zA-Z0-9][^$#\\\/t=]*:([^=]|$)/ {split($1,A,/ /);for(i in A)print A[i]}' `;

What could be the problem ?

I tried with the solution purposed but it provide an error:

make -qp | grep '^[a-z0-9-]\\+:'

Answer 1

what could be the problem ?

The problem is that this regular expression:

 /^[a-zA-Z0-9][^$#\\\\\\/t=]*:([^=]|$)/

does not match target names with hyphens ( - ) in them. As an unrelated matter, awk is a clumsy tool for what you appear actually to be doing with it; grep would be simpler to use:

make -qp | grep '^[a-z0-9-]\+:'

, which produces output

command:
command2:
another-command: