Bash脚本：删除最旧的目录

Question

I want to look for the oldest directory (inside a directory), and delete it. I am using the following:

rm -R $(ls -1t | tail -1)

ls -1t | tail -1 ls -1t | tail -1 does indeed gives me the oldest directory, the the problem is that it is not deleting the directory, and that it also list files.

How could I please fix that?

Answer 1

rm -R "$(find . -maxdepth 1 -type d -printf '%T@\t%p\n' | sort -r | tail -n 1 | sed 's/[0-9]*\.[0-9]*\t//')"

这也适用于名称包含空格，制表符或以“ - ”开头的目录。

Answer 2

这不是很漂亮，但它有效：

rm -R $(ls -lt | grep '^d' | tail -1  | tr " " "\n" | tail -1)

Answer 3

rm -R $(ls -tl | grep '^d' | tail -1 | cut -d' ' -f8)

Answer 4

find directory_name -type d -printf "%TY%Tm%Td%TH%TM%TS %p\n" | sort -nr | tail -1 | cut -d" " -f2 | xargs -n1 echo rm -Rf

如果它产生正确的结果，你应该删除rm之前的回声