错误：二进制％的操作数无效（有'double'和'double'）

Question

I have a program I am writing that lists 100,000 prime numbers. It works fine for 10 numbers, but after so many numbers they turn into negative values. I changed the ints to long ints and that did not change anything, then I changed them to doubles and I get the error listed in the title. What should my variable be? Keep in mind I am still new to programing. I also looked at some previous posts and did not see the answer.

 int is_prime(double x,char array[]){
 //doesnt use array but I put it in there

     double j=2;//divider
     for(j=2;j<=pow(x,0.5);j++){
         if((x%j==0)){
             return(0);
         }   //isnt prime  
     }
     return(1);// because it is prime.
 }

Answer 1

You can't use a double with the operator, you must have an int.

You should: #include <math.h> and then use the fmod function.

if(fmod(x,j)==0)

Full code:

 #include <math.h>
 int is_prime(double x,char array[]){
 //doesnt use array but I put it in there

     double j=2;//divider
     for(j=2;j<=pow(x,0.5);j++){
         if(fmod(x,j)==0){
             return(0);
         }   //isnt prime  
     }
     return(1);// because it is prime.
 }

Answer 2

You have two options:

1. Stick with the % operator, then you're required to cast the inputs to int s

    if(((int)x % (int)j) == 0) 

2. Include math.h and then use fmod :

    if(fmod(x, j) == 0) 

Answer 3

您的直接问题可以通过fmod解决，但是出于高价素数的目的，您最好还是查看一个大整数类，比如http://sourceforge.net/projects/cpp-bigint/因为你真正想要的是整数数学，并且随着事情的发展，使用浮点数可能会导致问题。