将数据插入3个相关表

Question

How to insert data into 3 related tables (SQL Server)

For example, I have tables Customer <-- Customer_Address --> Address After I insert data into Customer and Address, how do I insert the IDs from Customer and Address in to Customer_Address? (join table)

Thanks!

Answer 1

Use SCOPE_IDENTITY , @@IDENTITY can return a value from any scope:

DECLARE @CustomerId INT
DECLARE @AddressId INT

BEGIN TRANSACTION

  INSERT INTO CUSTOMER (blah, blah) values (blah, blah)
  SET @CustomerId = SCOPE_IDENTITY

  INSERT INTO ADDRESS (blah, blah) values (blah, blah)
  SET @AddressId = SCOPE_IDENTITY 

  INSERT INTO CUSTOMERADDRESS (CustomerId,AddressId) values (@CustomerId,@AddressId)

COMMIT TRANSACTION

Answer 2

If you want to insert more than one row you can use the output clause:

declare @insertedAddresses table (OriginalID int, AddressID int);
declare @insertedCustomers table (OriginalID int, CustomerID int);

insert into dbo.Addresses (AddressData)
output source.OriginalID, inserted.AddressID into @insertedAddresses
select AddressData from source;

insert into dbo.Customers (CustomerData)
output source.OriginalID, inserted.CustomerID into @insertedCustomers
select CustomerData from source;

insert into dbo.Customer_Address (AddressID, CustomerID)
select a.AddressID, c.CustomerID
from @insertedAddresses a inner join @insertedCustomers c on c.OriginalID=a.OriginalID;

Answer 3

If the IDs from the Customer and Address tables are Identity columns, you can store the new ID into a variable.

DECLARE @CustomerID int

SELECT @CustomerID = @@IDENTITY FROM TABLE CUSTOMER

Similar syntax could be used for the Address table. Then in your INSERT statement you can do this:

INSERT INTO Customer_Address (CustomerID, AddressID)
VALUES (@CustomerID, @AddressID)

Answer 4

use a transaction, and remember the identities. in sql server -

declare @CustomerId int
declare @AddressId int

begin tran
    insert into Customer (blah, blah) values (blah, blah)
    set @CustomerId = @@IDENTITY    --assuming there are no triggers
    insert into [Address] (blah, blah) values (blah, blah)
    set @AddressId = @@IDENTITY     --once again, no triggers to mess up the @@IDENTITY
    insert into CustomerAddress(CustomerId,AddressId) values (@CustomerId,@AddressId)
commit

Answer 5

Here is one way.

Declare CustomerID int, AddressID int


insert into Customer (list, of, fields) values (list, of, values)
select @CustomerID=scope_Identity()
insert into Address (list, of, fields) values (list, of, values)
select @AddressID =scope_Identity()

insert into Customer_Address (CustomerID, AddressID) values (@CustomerID, @AddressID)

Answer 6

If it is for an application, why don't just use Linq, you can accomplish things like this in just a few minutes, in a more compressive way and more thigh to the business logic model.

If not the I highly recommend the transaction and SCOPE_IDENTITY version, because if you are in a heavy loaded system, an other operation can do an insert and change the identity value so you will end with inconsistent data.