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为什么将 XML 反序列化为 Object 返回空值?

[英]Why deserialize XML into Object return null value?

I have a XML string like that:我有一个这样的 XML 字符串:

<?xml version="1.0" ?>
<result>
<vmeet_id>7121</vmeet_id>
<username>MT_Hue_QuangBinh_QuangTri</username>
<email></email>
<begin_date>2010-04-21 08:53</begin_date>
<expiry_date>2010-12-21 00:00</expiry_date>
<point></point>
<info>OK</info>
</result>

I want to deserialize it into an object, so I created this class:我想将它反序列化为一个对象,所以我创建了这个类:

[Serializable] 
[XmlRoot(ElementName = "result", IsNullable = false)]
public class UserInfo
{
    [XmlAttribute("vmeet_id")]
    public int UserID { get; set; }
    [XmlAttribute("username")]
    public string Username { get; set; } 
    [XmlAttribute("email")]
    public string Email { get; set; }
    [XmlAttribute("begin_date")]
    public DateTime BeginDate { get; set; }
    [XmlAttribute("expiry_date")]
    public DateTime ExpiryDate { get; set; }
    [XmlAttribute("point")]
    public string Point { get; set; }
    [XmlAttribute("info")]
    public string Info { get; set; }
}

and then use this code to deserialize:然后使用此代码反序列化:

var deserializer = new XmlSerializer(typeof(UserInfo));
        using (var stream = new StringReader(result))
        {
            UserInfo userInfo = (UserInfo)deserializer.Deserialize(stream);
            return userInfo;
        }

return value was not null, but all its properties was null value:返回值不为空,但它的所有属性都是空值:

<result vmeet_id="0" begin_date="0001-01-01T00:00:00" expiry_date="0001-01-01T00:00:00"/>

what is wrong here?这里有什么问题? Did I forgot something?我忘记了什么吗?

Thank you.谢谢你。

In your XML, all your 'vmeet' 'begin_date' are all elements , but in your UserInfo Class, you declare them as XMLAttribute .在您的 XML 中,您所有的 'vmeet' 'begin_date' 都是elements ,但在您的 UserInfo 类中,您将它们声明为XMLAttribute Try changing them to XMLElement should help.尝试将它们更改为XMLElement应该会有所帮助。

Use XmlDocument and Json to easily resolve result.使用 XmlDocument 和 Json 轻松解析结果。

        public static T XmlToModel<T>(string xml)
        {

            XmlDocument doc = new XmlDocument();
            doc.LoadXml(xml);

            string jsonText = JsonConvert.SerializeXmlNode(doc);

            T result = JsonConvert.DeserializeObject<T>(jsonText);

            return result;
        }

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