新构造函数引发异常后的对象指针状态 - C ++

Question

What is going to be the status of an object pointer when a new class constructor throws an exception in C++? Take the following code for example:

CMyClass * pobjMyClass = (CMyClass *)0xA5A5A5A5;

try
{
    pobjMyClass = new CMyClass(); // Exception thrown in constructor
}
catch ( ... ) {}

When this code executes what will the value of pobjMyClass be, after the exception is thrown? A pointer to an invalid instance of CMyClass , 0xA5A5A5A5 , NULL , some random uninitialized value, or something else? Thanks.

Answer 1

由于在赋值发生之前抛出异常，pobjMyClass将是以前的任何东西 - 在你的情况下，0xa5a5a5a5。