从db中检索数据并将其显示在php中的表中..看到这段代码有什么问题吗？

Question

  $db = mysql_connect("localhost", "root", "");
  $er = mysql_select_db("ram");
  $query = "insert into names values('$name','$add1','$add2','$mail')";
  $result = mysql_query($query);
  print "<p> Person's Information Inserted </p>";
  $result = mysql_query("SELECT * FROM names");
?>

<table border="2">
   <tr>
      <th>Name</th>
      <th>Address Line 1</th>
      <th>Address Line 2 </th>
      <th>E-mail Id </th>
    </tr>
    <? 
    while ($array = mysql_fetch_row($result));
    {
        print "<tr> <td>";
        echo $array[0]; 
        print "</td> <td>";
        echo $array[1]; 
        print "</td> <td>";
        echo $array[2]; 
        print "</td> <td>";
        echo $array[3]; 
        print "</td> </tr>";
    }
?>

Answer 1

Try this:

<?php

 # Init the MySQL Connection
  if( !( $db = mysql_connect( 'localhost' , 'root' , '' ) ) )
    die( 'Failed to connect to MySQL Database Server - #'.mysql_errno().': '.mysql_error();
  if( !mysql_select_db( 'ram' ) )
    die( 'Connected to Server, but Failed to Connect to Database - #'.mysql_errno().': '.mysql_error();

 # Prepare the INSERT Query
  $insertTPL = 'INSERT INTO `name` VALUES( "%s" , "%s" , "%s" , "%s" )';
  $insertSQL = sprintf( $insertTPL ,
                 mysql_real_escape_string( $name ) ,
                 mysql_real_escape_string( $add1 ) ,
                 mysql_real_escape_string( $add2 ) ,
                 mysql_real_escape_string( $mail ) );
 # Execute the INSERT Query
  if( !( $insertRes = mysql_query( $insertSQL ) ) ){
    echo '<p>Insert of Row into Database Failed - #'.mysql_errno().': '.mysql_error().'</p>';
  }else{
    echo '<p>Person\'s Information Inserted</p>'
  }

 # Prepare the SELECT Query
  $selectSQL = 'SELECT * FROM `names`';
 # Execute the SELECT Query
  if( !( $selectRes = mysql_query( $selectSQL ) ) ){
    echo 'Retrieval of data from Database Failed - #'.mysql_errno().': '.mysql_error();
  }else{
    ?>
<table border="2">
  <thead>
    <tr>
      <th>Name</th>
      <th>Address Line 1</th>
      <th>Address Line 2</th>
      <th>Email Id</th>
    </tr>
  </thead>
  <tbody>
    <?php
      if( mysql_num_rows( $selectRes )==0 ){
        echo '<tr><td colspan="4">No Rows Returned</td></tr>';
      }else{
        while( $row = mysql_fetch_assoc( $selectRes ) ){
          echo "<tr><td>{$row['name']}</td><td>{$row['addr1']}</td><td>{$row['addr2']}</td><td>{$row['mail']}</td></tr>\n";
        }
      }
    ?>
  </tbody>
</table>
    <?php
  }

?>

---

Notes, Cautions and Caveats

Your initial solution did not show any obvious santisation of the values before passing them into the Database. This is how SQL Injection attacks (or even un-intentional errors being passed through SQL) occur. Don't do it!

Your database does not seem to have a Primary Key. Whilst these are not, technically, necessary in all usage, they are a good practice, and make for a much more reliable way of referring to a specific row in a table, whether for adding related tables, or for making changes within that table.

You need to check every action, at every stage, for errors. Most PHP functions are nice enough to have a response they will return under an error condition. It is your job to check for those conditions as you go - never assume that PHP will do what you expect, how you expect, and in the order you expect. This is how accident happen...

My provided code above contains alot of points where, if an error has occured, a message will be returned. Try it, see if any error messages are reported, look at the Error Message, and, if applicable, the Error Code returned and do some research.

Good luck.

Answer 2

This is a very simple code I use and you manipulate it to change the colour and size of the table as you see fit.

First connect to the database:

<?php
$connect=mysql_connect('localhost', 'root', 'password');

mysql_select_db("name");
//here u select the data you want to retrieve from the db

$query="select * from tablename";

$result= mysql_query($query);

//here you check to see if any data has been found and you define the width of the table

If($result){

echo "<table width ='340' align='left'>
      <tr color ='#5D9951>";
$i=0;

    If(mysql_num_rows($result)>0)
    {
         //here you fetch the data from the database and print it in the respective columns   
        while($i<mysql_num_fields($result))
        {    
             echo "<th>".mysql_field_name($result, $i)."</th>";
             $i++;
        }
        echo "</tr>";

        $color=1;

        while($rows=mysql_fetch_array($result, MYSQL_ASSOC))
        {    
            If ($color==1){
                echo "<tr color='#'#cccccc'>";

                foreach ($rows as $data){
                    echo "<td align='center'>".$data. "</td>";
                }

                $color=2;
            }
            $color=1;
        }
     } else {
        echo"no results found";
        echo "</table>";
    } else {
        echo "error running query:".MYSQL_error();
}
?>

It's a very elementary piece of code but it helps if you are not used to using functions.

Answer 3

Here is the solution total html with php and database connections

   <!doctype html>
    <html lang="en">
    <head>
      <meta charset="UTF-8">
      <title>database connections</title>
    </head>
    <body>
      <?php
      $username = "database-username";
      $password = "database-password";
      $host = "localhost";

      $connector = mysql_connect($host,$username,$password)
          or die("Unable to connect");
        echo "Connections are made successfully::";
      $selected = mysql_select_db("test_db", $connector)
        or die("Unable to connect");

      //execute the SQL query and return records
      $result = mysql_query("SELECT * FROM table_one ");
      ?>
      <table border="2" style= "background-color: #84ed86; color: #761a9b; margin: 0 auto;" >
      <thead>
        <tr>
          <th>Employee_id</th>
          <th>Employee_Name</th>
          <th>Employee_dob</th>
          <th>Employee_Adress</th>
          <th>Employee_dept</th>
          <td>Employee_salary</td>
        </tr>
      </thead>
      <tbody>
        <?php
          while( $row = mysql_fetch_assoc( $result ) ){
            echo
            "<tr>
              <td>{$row\['employee_id'\]}</td>
              <td>{$row\['employee_name'\]}</td>
              <td>{$row\['employee_dob'\]}</td>
              <td>{$row\['employee_addr'\]}</td>
              <td>{$row\['employee_dept'\]}</td>
              <td>{$row\['employee_sal'\]}</td> 
            </tr>\n";
          }
        ?>
      </tbody>
    </table>
     <?php mysql_close($connector); ?>
    </body>
    </html>

Answer 4

在你的while语句只需更换mysql_fetch_row与mysql_fetch_array或mysql_fetch_assoc ...取其作品...

Answer 5

<html>
    <head>
        <meta charset="UTF-8">
        <title>LoginDB</title>
    </head>
    <body>

        <?php
        $con=  mysqli_connect("localhost", "root", "", "detail");
<!-- detail is the database in MySqli Database -->
        if(!$con)
       {
           die('not connected');
       }
            $con=  mysqli_query($con, "select * from signup");
<!-- signup is the table in the detail_Database -->
       ?>
        <div>
            <td>Login Page Database</td>
         <table border="1">
            <th> First Name</th>
                    <th>Last Name</th>
                    <th>UserName</th>
                     <th>Password</th>
                    <th>Gender</th>
                    <th>D.O.B.</th>
                    <th>Phone Number</th>
                    <th>Address</th>

            </tr>

        <?php

             while($row=  mysqli_fetch_array($con))
<!-- Fetch each row from signup Table  -->
             {
                 ?>
            <tr>
                <td><?php echo $row['FirstName']; ?></td>
                <td><?php echo $row['LastName']; ?></td>
                <td><?php echo $row['Username']; ?></td>
                <td><?php echo $row['Password'] ;?></td>
                <td><?php echo $row['Gender'] ;?></td>
                <td><?php echo $row['DOB'] ;?></td>
                <td><?php echo $row['PhoneNumber'] ;?></td>
                <td><?php echo $row['Address'] ;?></td>
            </tr>
        <?php
             }
             ?>
             </table>
            </div>
    </body>
</html>

Answer 6

When you are connecting database you are not passing your connection variable. That is the error