PHP代码显示数据库数据

Question

Hi guys I have a problem with my PHP, What I am trying to achieve is this:

<li><a href="main.html" class="title">Product name from DB</a>
        <strong>&pound;499<a href="main.html"><img src="images/thumb.png" alt="Product name from DB"/></a></strong>
  </li>

and here is my code with php:

<ul id="items">
    <?php while($product_data = mysql_fetch_array($query_product_result))
  {
    $num_rows_products = $num_rows_products - 1;
    Print "<li><a href = 'main.php?prodid=" . $product_data["product_id"] . " <strong> Name:  " . $product_data["title"] . "</strong></a>";
    Print "<strong>Price: &pound;" . $product_data["price"] .  "'><img src='images/" . $product_data["mainImageThumbnail"] . "' alt='Product image' /></a></strong></li>";
    if($num_rows_products > 0)
            Print '<p> nu products ? wtf</p>';
  }
  ?>

For some reason all I get is an image with a hyperlink, no title and no price, any chance you can spot the mistake?

Answer 1

Your not closing the <a> tag properly. See the code below. Notice the missing ">" in your code?

Print "<li><a href = 'main.php?prodid=" . $product_data["product_id"] . "'> <strong> Name:  " . $product_data["title"] . "</strong></a>";
    Print "<strong>Price: &pound;" . $product_data["price"] .  "<img src='images/" . $product_data["mainImageThumbnail"] . "' alt='Product image' /></a></strong></li>";

Answer 2

Use Echo instead. Print won't displays concatenated string.

 <ul id="items">
        <?php while($product_data = mysql_fetch_array($query_product_result))
      {
        $num_rows_products = $num_rows_products - 1;
        echo "<li><a href = 'main.php?prodid=" . $product_data["product_id"] . " <strong> Name:  " . $product_data["title"] . "</strong></a>";
        echo "<strong>Price: &pound;" . $product_data["price"] .  "'><img src='images/" . $product_data["mainImageThumbnail"] . "' alt='Product image' /></a></strong></li>";
        if($num_rows_products > 0)
                echo '<p> nu products ? wtf</p>';
      }
      ?>