C ++将动态大小的2D数组传递给函数

Question

I'm trying to figure out how to pass 2D array, which is constructed dynamically to a function. I know that number of columns must be specified, but it my case it depends on user input.

Are there any workarounds?

Example:

// Some function
void function(matrix[i][j]) {
// do stuff
}
// Main function
int N;
cout << "Size: ";
cin >> N;

int matrix[N][N];

for (int i=0;i<N;i++) { // 
 for (int j=0;j<N;j++) { 
  cin >> matrix[N][N];
 }
}

sort(matrix);

You get the idea :)

Answer 1

If you're on C++, the reasonable options are to:

• use boost::multi_array (recommended), or
• make your own 2D array class. Well, you don't have to, but encapsulating 2D array logic in a class is useful and makes the code clean.

Manual 2D array indexing would look like this:

void func(int* arrayData, int arrayWidth) {
    // element (x,y) is under arrayData[x + y*arrayWidth]
}

But seriously, either wrap this with a class or enjoy that Boost already has that class ready for you. Indexing this manually is tiresome and makes the code more unclean and error-prone.

---

edit

http://gcc.gnu.org/onlinedocs/gcc/Variable-Length.html says that C99 has one more solution for you:

void func(int len, int array[len][len]) {
   // notice how the first parameter is used in the definition of second parameter
}

Should also work in C++ compilers, but I haven't ever used this approach.

Answer 2

In C++, the compiler can figure out the size, since it's part of the type. Won't work with dynamically sized matrices though.

template<size_t N, size_t M>
void function(int (&matrix)[N][M])
{
  // do stuff
}

EDIT: In GCC only, which is required for your code defining the array, you can pass variable-length arrays directly:

void func(int N, int matrix[N][N])
{
  //do stuff
}

See the gcc documentation

Answer 3

/*******************************************************\
*                                                       *
* I am not claiming to be an expert, but I think I know *
* a solution to this one. Try using a Vector Container  *
* instead of an array. Here is an example below:        *
*                                                       *
* Load the target file with a Multiplication Table      *
*                                                       *
*                                                       *
\*******************************************************/

// reading a text file
#include <iostream>
#include <fstream>
#include <string>
#include <vector>


std::string user_file;
int user_size = 2;
void array_maker(int user_size, std::string user_file);

int main () {
  std::cout << "Enter the name of the file for your data: ";
  std::cin >> user_file;
  std::cout << std::endl;
  std::cout << "Enter the size for your Multiplication Table: ";
  std::cin >> user_size;

  // Create the users Multiplication data
     array_maker(user_size, user_file);

  return (0);
}

void array_maker(int user_size, std::string user_file)
{
  // Open file to write data & add it to end of file
  std::ofstream target_file(user_file,std::ios::out | std::ios::app);

  // Declare the vector to use as a runtime sized array
  std::vector<std::vector<int>> main_array;

  // Initialize the size of the vector array
  main_array.resize(user_size+1); // Outer Dimension
  for (int i=0; i <= user_size; ++i) // Inner Dimension
  {
    main_array[i].resize(user_size+1);
  }

  for (int i=0; i<=user_size; ++i) 
  {
    for (int j=0; j<=user_size; ++j)
    {
      main_array[i][j] = i * j;
      // output line to current record in file
      target_file << i << "*" 
              << j << "=" 
              << main_array[i][j] << " "
              << "EOR"   // End of Record 
              << std::endl;

    } // Close Inner For
  } // Close Outer For
  // close file
  target_file.close();

} // Close array_maker function

Answer 4

to pass multi dimensional arays into method the compiler needs to know the depth of each field, so one solution is to use templates and call method in a normal way and the compiler will guess the size of each field.

template <size_t m>
void method(int M[][m])
{
    for(int i=0; i<m; ++i)
        for(int j=0; j<m; ++j)
        {
            // do funny stuff with M[i][j]
        }
}

int main()
{
    int M[5][5] = { {1,0,1,1,0}, {0,1,1,1,0}, {1,1,1,1,1}, {1,0,1,1,1}, {1,1,1,1,1} };
    method(M);
    // also you can call with method<5>(M)
    // if you have different sizes for each dimension try passing them in args
    return 0;
}

Answer 5

You can do void function (int** __matrix, int32_t __row, int32_t __column) __row - max rows __column - max columns.

You will need those params to find out the limits of the array.

Answer 6

Just add another parametrs to your function - row_number and column_number . Arrays are not object in C++ so they don't store any additional information about themselfs.

Answer 7

If you pass in the array identifier (as a pointer to a pointer) you will need to use pointer arithmetic:

void function(int** matrix, int num_rows, int num_cols) {
    Assert(matrix!=NULL && *matrix!=NULL && num_rows>0 && num_cols>0);

    for(int i=0; i<num_rows; i++) {
        for(int j=0; j<num_cols; j++) {
            // cannot index using [] like matrix[i][j]
            // use pointer arithmetic instead like:
            // *(matrix + i*num_cols + j)

        }
    }
}

Answer 8

int r, c
int *matrix = new int[r,c];
for (int i = 0; i < r; i++)
    {
        /*cout << "Enter data" << endl;*/
        for (int j = 0; j < c; j++)
        {
            cin >> matrix[i,j];

        }
    }

Answer 9

虚函数（int＆matrix [] []）