在javascript中进行类型检查

Question

How can I check if a variable is currently an integer type? I've looked for some sort of resource for this and I think the === operator is important, but I'm not sure how to check if a variable is an Integer (or an Array for that matter)

Answer 1

A variable will never be an integer type in JavaScript — it doesn't distinguish between different types of Number.

You can test if the variable contains a number, and if that number is an integer.

(typeof foo === "number") && Math.floor(foo) === foo

If the variable might be a string containing an integer and you want to see if that is the case:

foo == parseInt(foo, 10)

Answer 2

These days, ECMAScript 6 (ECMA-262) is "in the house". Use Number.isInteger(x) to ask the question you want to ask with respect to the type of x:

js> var x = 3
js> Number.isInteger(x)
true
js> var y = 3.1
js> Number.isInteger(y)
false

Answer 3

A number is an integer if its modulo %1 is 0-

function isInt(n){
    return (typeof n== 'number' && n%1== 0);
}

This is only as good as javascript gets- say +- ten to the 15th.

isInt(Math.pow(2,50)+.1) returns true , as does Math.pow(2,50)+.1 == Math.pow(2,50)

Answer 4

A clean approach

You can consider using a very small, dependency-free library like Issable . Solves all problems:

// at the basic level it supports primitives
let number = 10
let array = []
is(number).number() // returns true
is(array).number() // throws error

// so you need to define your own:
import { define } from 'issable'
// or require syntax
const { define } = require('issable')

define({
    primitives: 'number',
    nameOfTyping: 'integer',
    toPass: function(candidate) {
        // pre-ECMA6
        return candidate.toFixed(0) === candidate.toString()
        // ECMA6
        return Number.isInteger(candidate)
    }
})
is(4.4).custom('integer') // throws error
is(8).customer('integer') // returns true

If you make it a habit, your code will be much stronger. Typescript solves part of the problem but doesn't work at runtime, which is also important.

function test (string, boolean) {
    // any of these below will throw errors to protect you
    is(string).string()
    is(boolean).boolean()

    // continue with your code.
}

Answer 5

I know you're interested in Integer numbers so I won't re answer that but if you ever wanted to check for Floating Point numbers you could do this.

function isFloat( x )
{
    return ( typeof x === "number" && Math.abs( x % 1 ) > 0);
}

Note: This MAY treat numbers ending in .0 (or any logically equivalent number of 0 's) as an INTEGER. It actually needs a floating point precision error to occur to detect the floating point values in that case.

Ex.

alert(isFloat(5.2));   //returns true
alert(isFloat(5));     //returns false
alert(isFloat(5.0));   //return could be either true or false

Answer 6

Quite a few utility libraries such as YourJS offer functions for determining if something is an array or if something is an integer or a lot of other types as well. YourJS defines isInt by checking if the value is a number and then if it is divisible by 1:

function isInt(x) {
  return typeOf(x, 'Number') && x % 1 == 0;
}

The above snippet was taken from this YourJS snippet and thusly only works because typeOf is defined by the library. You can download a minimalistic version of YourJS which mainly only has type checking functions such as typeOf() , isInt() and isArray() : http://yourjs.com/snippets/build/34,2

Answer 7

You may also have a look on Runtyper - a tool that performs type checking of operands in === (and other operations).
For your example, if you have strict comparison x === y and x = 123, y = "123" , it will automatically check typeof x, typeof y and show warning in console:

Strict compare of different types: 123 (number) === "123" (string)

Answer 8

Try this code:

 alert(typeof(1) == "number");